I want to take input in array of bool
bool bmp[32];
And this will be the program interaction.
Enter binary number : 10101
I want to store user input of '10101' in array of bool like.
bmp[32]={1,0,1,0,1};
Please help!!
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3 Answers
Since this is C++, let's use std::bitset:
std::cout << "Enter binary number : ";
std::bitset<32> b;
std::cin >> b;
It's not a bool array like you requested - but it's way better.
3 Comments
antonpp
...or a way worse=) In my personal opinion I would use a single
int as a binary mask for this case.
Barry
@Anton And if you want 132 bits instead of 32?
antonpp
then it is another story to tell. I simply mean that the solution strongly depends on the task and std::bitset is not always the right choice when you need some work to be done over the bloody bits.
This should work, but try something out on your own next time (and post the code you tried).
bool b[ 32 ];
std::string str = "10101";
for ( std::string::size_type i = 0U; i < str.length(); ++i )
b[ i ] = str[ i ] == '1';
Or maybe
std::vector< bool > b;
std::string str = "10101";
b.reserve( str.length() );
for ( const char c : str )
b.push_back( c );
Comments
Nothing fancy, just read data and store it to array like this:
#include <string>
#include <cstdio>
int main() {
std::string str;
std::cout << "Enter binary number : ";
std::cin >> str;
bool b[32];
std::size_t size = 0;
for (auto c : str) {
b[size++] = c == '1';
}
// you are all set now.
return 0;
}