jquery pass radio button array

Question

I am having a bit of trouble figuring out how to pass the selected radio button value thru JQUERY and ultimately to php.

The following is the html markup:

    <li class="gchoice_1_14_0">
        <input name="donation[]" type="radio" value="25" id="donation" tabindex="14">
        <label for="choice_1_14_0" id="label_1_14_0">$25</label>
    </li>

    <li class="gchoice_1_14_1">
        <input name="donation[]" type="radio" value="50" id="donation" tabindex="15">
        <label for="choice_1_14_1" id="label_1_14_1">$50</label>
    </li>

    <li class="gchoice_1_14_2">
        <input name="donation[]" type="radio" value="100" id="donation" tabindex="16">
        <label for="choice_1_14_2" id="label_1_14_2">$100</label>
    </li>

    <li class="gchoice_1_14_3">
        <input name="donation[]" type="radio" value="350" id="donation" tabindex="17">
        <label for="choice_1_14_3" id="label_1_14_3">$350 - Guardian Angel Sponsorship – a donation at this level provides interview and follow-up services for one child</label>
    </li>

    <li class="gchoice_1_14_4">
        <input name="donationother" type="radio" value="other_amount" id="donation" tabindex="18" onfocus="jQuery(this).next('input').focus();">
        <input id="donation_other" name="donation_other" type="text" value="" onfocus="jQuery(this).prev(&quot;input&quot;).attr(&quot;checked&quot;, true); if(jQuery(this).val() == &quot;Other&quot;) { jQuery(this).val(&quot;&quot;); }" onblur="if(jQuery(this).val().replace(&quot; &quot;, &quot;&quot;) == &quot;&quot;) { jQuery(this).val(&quot;Other&quot;); }" tabindex="18">
    </li>

Then I am attempting to pass the data thru jquery so it can be caught via php. This is my present jquery markup:

        post_data = {
            'user_name'     : $('input[name=full_name]').val(), 
            'user_email'    : $('input[name=email]').val(), 
            'address'   : $('input[name=address]').val(), 
            'address2'  : $('input[name=address2]').val(), 
            'city'  : $('input[name=city]').val(), 
            'state' : $('input[name=state]').val(), 
            'zip'   : $('input[name=zip]').val(), 
            'ccnum' : $('input[name=ccnum]').val(), 
            'expmonth'  : $('select[name=expmonth]').val(), 
            'expyear'   : $('select[name=expyear]').val(), 
            'cardname'  : $('input[name=cardname]').val(),
            'ccvcode'   : $('input[name=ccvcode]').val(),
            'donation'  : $('input[name=donation]').val(),
            'donation_other'    : $('input[name=donation_other]').val(),
            'phone_number'  : $('input[name=phone2]').val(), 
            'subject'       : $('select[name=subject]').val(), 
            'msg'           : $('textarea[name=message]').val()
        };

When I review the passing in Chrome's developer tools, the donation field/s are not being passed at all.

Could someone explain what I am missing with this? I have tried various ways of passing the donation value, but to no avail.

Thank you!

First of all, it's invalid to have multiple elements with the same id — LcSalazar
– LcSalazar, Commented Apr 17, 2015 at 20:12
You're not actually posting data. You are just putting the values into variable. Check out this api.jquery.com/jquery.ajax. Also this seems like you should just form submit the data. Why do you want to do this with Jquery? — mattfetz
– mattfetz, Commented Apr 17, 2015 at 20:18
because of the wonderful effects that can be done with jquery — MrTechie
– MrTechie, Commented Apr 17, 2015 at 20:20

MrTechie · Accepted Answer · 2015-04-17 20:36:07Z

1

For those who research and come across this post, the proper answer to my question is to detect the value that has been checked by doing this:

'donation'  : $('input[name=donation]:checked').val(),

answered Apr 17, 2015 at 20:36

MrTechie

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