python curl execute command with parameter

Question

I need to execute the following command

curl -v -H 'X-Auth-User: myaccount:me' -H 'X-Auth-Key: secretpassword' http://localhost:8080/auth/v1.0/

when I run this from terminal it works perfectly. and gives me result like following

* About to connect() to localhost port 8080 (#0)
*   Trying ::1...
* Connection refused
*   Trying 127.0.0.1...
* Connected to localhost (127.0.0.1) port 8080 (#0)
> GET /auth/v1.0/ HTTP/1.1
> User-Agent: curl/7.29.0
> Host: localhost:8080
> Accept: */*
> X-Auth-User: myaccount:me
> X-Auth-Key: secretpassword
> 
< HTTP/1.1 200 OK
< X-Storage-Url: http://localhost:8080/v1/AUTH_myaccount
< X-Auth-Token: AUTH_tk8bf07349d36041339450f0b46a2adc39
< Content-Type: text/html; charset=UTF-8
< X-Storage-Token: AUTH_tk8bf07349d36041339450f0b46a2adc39
< Content-Length: 0
< X-Trans-Id: tx99a9e2a129f34ab487ace-00553cb059
< Date: Sun, 26 Apr 2015 09:31:05 GMT
< 
* Connection #0 to host localhost left intact

But i need to run this from python. I have used subprocess.call and subprocess.popen in the following way

import subprocess
subprocess.call(["curl", "-v -H 'X-Auth-User: myaccount:me' -H 'X-Auth-Key: secretpassword' http://localhost:8080/auth/v1.0/"], shell=False)

but I am getting the followin error

curl: option -v -H 'X-Auth-User: myaccount:me' -H 'X-Auth-Key: secretpassword' http://localhost:8080/auth/v1.0/: is unknown
curl: try 'curl --help' or 'curl --manual' for more information

using popen

result = subprocess.Popen(["curl", "-v -H 'X-Auth-User: myaccount:me' -H 'X-Auth-Key: secretpassword' http://localhost:8080/auth/v1.0/"])
print(result)

and getting error for this

curl: option -v -H 'X-Auth-User: myaccount:me' -H 'X-Auth-Key: secretpassword' http://localhost:8080/auth/v1.0/: is unknown
curl: try 'curl --help' or 'curl --manual' for more information
<subprocess.Popen object at 0x7fd003d82cd0>

How to fix this???

JuniorCompressor · Accepted Answer · 2015-04-26 09:36:48Z

4

Since call needs to pass an array of command line arguments, you can split the command line yourself and call like this:

subprocess.call([
    "curl", "-v", "-H", "X-Auth-User: myaccount:me", "-H", 
    "X-Auth-Key: secretpassword", "http://localhost:8080/auth/v1.0/"
], shell=False)

answered Apr 26, 2015 at 9:36

JuniorCompressor

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