I have to do the following thing"
Write a function that takes a string as input and returns a string composed of only the odd indexes of the string. Note: enumerate() is not available.
now the code I can come up with is
def odd_string(data):
result = ""
for i in (data):
return data[0],data[2],data[4]
print (odd_string("hello"))
how do i actually append these values to a string and how do I make it so that each odd number will be added(without having to write them all out)
Stride indexing (you're probably familiar with it from range()) works well here.
def odd_string(data):
return data[1::2]
0, 2, and 4 are clearly not odd indices.
return statement should be return data[::2].
Something like this maybe?
def odd_string(data):
result = ''
for c in range(0, len(data)):
if (c % 2 == 1):
result += data[c]
return result
%2==1 as well, but the assignment itself needs clarification.(c % 2 == 1) with c%2, as a truthy value.You can also try something like:
newlist = list(range(10))
print newlist[1::2]
while i<T:
temp =input()
even=""
odd=""
j=0
k=1
while j<len(temp):
even = even+temp[j]
j+=2
while k<len(temp):
odd = odd+temp[k]
k+=2
i+=1
print (even,odd)
nhasn//2odd indices, so you could just do''.join(map(str, range(1, len(s), 2))). That would give you a string composed of the indices. Surely that's not what the question means, but it is what it asked for.