% in url http request java [duplicate]

Question

I'm trying to do an http request in java but I get this error:

java.lang.IllegalArgumentException: Invalid % sequence: %Ne in query at index 80:

try {
     HttpClient Client = new DefaultHttpClient();
     String URL = "Example.com";
     HttpGet httpget = new HttpGet(URL);
     ResponseHandler<String> responseHandler = new BasicResponseHandler();
     String SetServerString = Client.execute(httpget, responseHandler);
     Log.e("iets",SetServerString);

} 
catch (ClientProtocolException e) {
     e.printStackTrace();
} 
catch (IOException e) {
     e.printStackTrace();
}

It seems I cant use the character '%' in the query. But the thing is that I really need to use the '%' since it represents a space in my echonest.php.

How can I solve this problem?

thanks in advance

Have you tried encoding the url? URLEncoder.encode(URL, "utf-8"); — Hans Vn
– Hans Vn, Commented Apr 30, 2015 at 8:13
You may want to use URI templates; I happen to have a library for that, but others also exist. In particular, if you use Guava, it has Escapers for that. — fge
– fge, Commented Apr 30, 2015 at 8:25

Veselin Davidov · Accepted Answer · 2015-04-30 08:13:40Z

2

% is used to encode special characters in URLs. To encode the actual "%" character you need to use %25 The url will become: http://bertenbevers.be/ProjectICT4/echonest.php?title=stormwatch&artist=Helvetic%25Nerds

There are ready made libraries to encode urls. It will help avoid other strange symbols like spaces, slashes etc.

answered Apr 30, 2015 at 8:13

Veselin Davidov

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Comments

ComputerFellow · Accepted Answer · 2015-04-30 08:22:43Z

1

You should encode your URL using URLEncoder.

String URL = "http://bertenbevers.be/ProjectICT4/echonest.php?title=stormwatch&artist=" + URLEncoder.encode("Helvetic%Nerds", "UTF-8");

edited Apr 30, 2015 at 8:22

answered Apr 30, 2015 at 8:13

ComputerFellow

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1 Comment

laalto Over a year ago

Didn't downvote but you're encoding too much, such as the = and &. Many other answers have the same problem.

Beunzor · Accepted Answer · 2015-05-04 17:36:37Z

0

Use URLEncoder like this:

String URL = "www.example.com"?title=stormwatch&artist=Helvetic"+URLEncoder.encode("%","UTF-8")+"Nerds";

Modify your code:

try {
                HttpClient Client = new DefaultHttpClient();
                String URL = "www.example.com/?title=stormwatch&artist=Helvetic"+URLEncoder.encode("%","UTF-8")+"Nerds";
                HttpGet httpget = new HttpGet(URL);
                ResponseHandler<String> responseHandler = new BasicResponseHandler();
                String SetServerString = Client.execute(httpget, responseHandler);
                Log.e("iets",SetServerString);

            } catch (ClientProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }

edited May 4, 2015 at 17:36

Beunzor

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answered Apr 30, 2015 at 8:19

Harsh Dattani

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1 Comment

ComputerFellow Over a year ago

+"Nerds" - you've forgotten to put that under double quotes.

karvin.developer · Accepted Answer · 2015-04-30 08:16:08Z

-1

Since you are using a special character in your URL you should user URLEncoder.encode(<your URL>) method

for example :- String url = "http://bertenbevers.be/ProjectICT4/echonest.php?"+URLEncoder.encode("title=stormwatch&artist=Helvetic%Nerds");

Hope this might help you in solving your problem

answered Apr 30, 2015 at 8:16

karvin.developer

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