Regex Invalid Escape Sequence on Split String

Question

I'm attempting to make my String array split on whitespace or any punctuation besides the dash character. This is my attempt:

String[] temp = lowerCased.split("\p{Blank}\\\p{Punct}&&[^-]]");

I'm getting the Invalid Escape Sequence and I figure it has to do with Java's need for a double backslash, but I can't pinpoint where exactly it's going wrong. I put it into one of the Regex emulation programs and it seemed to get the result I was going for.

The first backslash is not escaped, it should be. There are three backslashes in the middle when two backslashes will do. Also you have a hanging ]. — Jonny Henly
– Jonny Henly, Commented May 1, 2015 at 6:59

sol4me · Accepted Answer · 2015-05-01 07:06:46Z

1

The backslashes are not escaped properly, try this. There is also a left square bracket missing at the beginning.

String[] temp = "".split("[\\p{Blank}\\\\p{Punct}&&[^-]]");

edited May 1, 2015 at 7:06

answered May 1, 2015 at 7:00

sol4me

15.8k6 gold badges37 silver badges35 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Regex Invalid Escape Sequence on Split String

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related