How to return array in c? [duplicate]

Question

How to return array in C?

    #include <stdio.h>
    #include <string.h>
    #include <stdlib.h>

    int main()

    {
        int func(int);
        printf("%d",func(1));

    }

    int func(int n)
    {
        int i,arr[5]; //or int *arr=(int*)malloc(5);
        for (i=0; i<5; i++) {
            arr[i]=n++;
        }
        return arr;
    }

I want to get result '11111', but this code's result is '1606416336'.
What can I do to solve this problem?

You can't return a local array in C. You need to allocate it dynamically with malloc(). — Barmar
– Barmar, Commented May 5, 2015 at 0:14
You can't ever return an array in C. It's an annoying limitation. You can, however, return a struct that contains an array, or have the caller create an array and pass a pointer to it as an argument. — Stack Exchange Broke The Law
– Stack Exchange Broke The Law, Commented May 5, 2015 at 0:15
int func(int n) { int i, v = 0; for (i=0; i<5; i++) { v = v * 10 + n; } return v; } — BLUEPIXY
– BLUEPIXY, Commented May 5, 2015 at 0:16

BLUEPIXY · Accepted Answer · 2015-05-05 00:45:17Z

0

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    int *func1(int);
    int func2(int);
    int *p = func1(1);
    int i;
    for(i=0; i < 5; ++i){
        printf("%d", p[i]);
    }
    printf("\n");
    free(p);

    printf("%d",func2(1));
    return 0;
}

int *func1(int n){
    int i;
    int *arr=(int*)malloc(5*sizeof(int));
    for (i=0; i<5; i++) {
        arr[i]=n;
    }
    return arr;
}

int func2(int n){
    int i, v = 0;
    for (i=0; i<5; i++){
        v = v * 10 + n;
    }
    return v;
}

answered May 5, 2015 at 0:45

BLUEPIXY

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