Batch command and error handling

Question

I am using this code in a batch file:

for /f %%f in ('"net user %user% /domain | findstr /i %group%"') do set /a i=%i%+1

It looks like no matter what %user% you type in it will still set %i%+1 equaling 1... even if the %user% is not found.

If the %user% is not found, NET USER reports saying the user was not found, but because %i%=1 it continues on in the script.

How would I go about getting this to work? If the %user% is not found in /Domain then %i% needs to = 0

npocmaka · Accepted Answer · 2015-05-07 16:52:40Z

2

for /f %%f in ('"net user %user% /domain ^| findstr /i %group%"') do set /a i=%i%+1

you need to escape the pipe as it is with higher prio than for loop.

answered May 7, 2015 at 16:52

npocmaka

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4 Comments

dbenham Over a year ago

Also, the DO clause could be simplified to set /a i+=1

user2150312 Over a year ago

@npocmaka From what I see you only escaped the pipe. When I add the escape (carrot) it reports /I is an unknown option in NET. This error happens whether the user is good or not. Any other suggestions?

JosefZ Over a year ago

for /f %%f in ('net user %user% /domain ^| findstr /i "%group%"') do set /a i+=1 see double quoting

JosefZ Over a year ago

Or even 'net user %user% /domain 2^>NUL ^| findstr /i "%group%"' to suppress displaying error messages...

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