multiple variables using foreach as?

Question

I'm trying to fetch YouTube thumbnails and video id's using the API v3 and echo them into HTML, however I need to echo two variables at the same time. At the moment I have the following:

<?php
$url = 'https://www.googleapis.com/youtube/v3/playlistItems?part=snippet&maxResults=12&playlistId=UUDWdi7vjr3ac_z_VMMeiL_Q&key=*************************';
$data = file_get_contents($url);
if ((preg_match_all("/\"videoId\":\s*\"(.+)\"/", $data, $video_get) ) && (preg_match_all("/\"title\":\s*\"(.+)\"/", $data, $title_get) ) ) {
    foreach (($video_get[1] as $videoid) && foreach ($title_get[1] as $title ) ){
        echo ("<div id=\"video-thumb\" class=\"col-sm-6\"><img id=\"video-thumb-320180\" src=\"https://i.ytimg.com/vi/'.$videoid.'/mqdefault.jpg\"><div class=\"video-hover\"><img class=\"play-hover\" src=\"images/play.png\"></div><h2 class=\"video-title\"><i><a href=\"https://youtube.com/watch?v='.$videoid.'\">'.$title.'</a></h2></i></div>");
        }
    }
else {
    echo ("Error fetching uploads!")
}
?>

However after trying this it seems I cannot use foreach as && foreach as. What's the solution here?

It would help to see a sample of the file_get_contents() output. — Stuart Wagner
– Stuart Wagner, Commented May 8, 2015 at 1:35
Actually, that API returns JSON. You don't need to preg_match anything. Just use json_decode(). — Stuart Wagner
– Stuart Wagner, Commented May 8, 2015 at 1:37
As stated on the comment to the other answer. I'm very new to PHP. How does the json format help me and how would I get my video and title elements from it? — STiGYFishh
– STiGYFishh, Commented May 8, 2015 at 1:39

Jonathan · Accepted Answer · 2015-05-08 02:09:23Z

1

Not sure why you're trying to do preg_match() ... but that data is json, just json_decode() it and you're done.

$url = 'https://www.googleapis.com/youtube/v3/playlistItems?part=snippet&maxResults=12&playlistId=UUDWdi7vjr3ac_z_VMMeiL_Q&key=AIzaSyBYG6nKkdddYT2NXg987kljPrKqsCVXcNQ';
/** data is in an array **/
$data = json_decode(file_get_contents($url), true);
foreach($data['items'] as $row) {
    echo ("
    <div id=\"video-thumb\" class=\"col-sm-6\">
        <img id=\"video-thumb-320180\" src=\"https://i.ytimg.com/vi/".$row['snippet']['resourceId']['videoId']."/mqdefault.jpg\">
        <div class=\"video-hover\">
            <img class=\"play-hover\" src=\"images/play.png\">
        </div>
        <h2 class=\"video-title\">
            <i><a href=\"https://youtube.com/watch?v=".$row['snippet']['resourceId']['videoId']."\">" . $row['snippet']['title']."</a></i>
        </h2>
    </div>");
}

response (from documentation)

{
  "kind": "youtube#playlistItemListResponse",
  "etag": etag,
  "nextPageToken": string,
  "prevPageToken": string,
  "pageInfo": {
    "totalResults": integer,
    "resultsPerPage": integer
  },
  "items": [
    {
      "kind": "youtube#playlistItem",
      "etag": etag,
      "id": string,
      "snippet": {
        "publishedAt": datetime,
        "channelId": string,
        "title": string,
        "description": string,
        "thumbnails": {
          (key): {
            "url": string,
            "width": unsigned integer,
            "height": unsigned integer
          }
        },
        "channelTitle": string,
        "playlistId": string,
        "position": unsigned integer,
        "resourceId": {
          "kind": string,
          "videoId": string,
        }
      },
      "contentDetails": {
        "videoId": string,
        "startAt": string,
        "endAt": string,
        "note": string
      },
      "status": {
        "privacyStatus": string
      }
    }
  ]
}

edited May 8, 2015 at 2:09

answered May 8, 2015 at 1:35

Jonathan

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9 Comments

STiGYFishh Over a year ago

Sorry I'm very new to PHP. How does the json format help me and how would I get my video and title elements from it?

Jonathan Over a year ago

json stands for .. JavaScript Object Notation. You will either see that or xml for most apis, it's extremely easy to convert it into workable code.

Stuart Wagner Over a year ago

JSON is basically a flattened (serialized) object or array. It's how most APIs return request data.

Jonathan Over a year ago

I recommend that you read this page for the full documentation, developers.google.com/youtube/v3/code_samples

Jonathan Over a year ago

here is the relevant documentation about json_decode php.net/manual/en/function.json-decode.php

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