Executing php script in perl with GET variables in url

Question

I have a perl script that executes a php script:

my $phpOutput = `/usr/bin/php /bart/bart.php`;

this works perfectly fine. now i want to add some variables to the url.

my $phpOutput = `/usr/bin/php /bart/bart.php?data=1`;

this fails.

Could not open input file: /bart/bart.php?data=1

any ideas why?

That looks like it is just executing it in the shell. Cant use php.net/manual/en/reserved.variables.argv.php? — chris85
– chris85, Commented May 8, 2015 at 20:43
This answer has kind of an interesting way to handle this. But it looks like you will need to change the PHP script one way or another to be able to handle calling it this way. — Don't Panic
– Don't Panic, Commented May 8, 2015 at 20:55

Joel Hinz · Accepted Answer · 2015-05-08 20:44:50Z

5

The ?x=y syntax is for web servers, whereas the CLI expects arguments separated by space after the filename. The way you've written it, PHP thinks that ?data=1 is part of the filename.

You could do

my $phpOutput = `/usr/bin/php /bart/bart.php 1`;

and use the $argv array to retrieve the argument 1 from within the PHP script. Since it's the first argument, it would be $argv[1] (the 0th index is the script name).

answered May 8, 2015 at 20:44

Joel Hinz

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2 Comments

bart2puck Over a year ago

ok, thank you. Now what if that "1" is a variable....my $phpOutput = /usr/bin/php /bart/bart.php $someVar; would this work?

Joel Hinz Over a year ago

Sure, I see no reason it shouldn't.

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