how to use json_encode without PHP 5.2

Question

I've written a CMS which uses the PHP function json_encode to send some data back via an Ajax Request.

Unfortunately, I'm trying to load it onto a server which is running PHP version 5.1, the json_encode PHP function is not available on versions of PHP before 5.2.0.

Does anyone know of a way to encode a PH array as JSON without using the inbuilt json_encode function?

EDIT

I've used Pekka's function, but now I find JQuery won't parse the result as expected. Even though Firebug shows JSON being passed back through. My firebug window looks like this:

and my jquery looks like this:

     $.ajax({
            type: "GET",
            url: "includes/function/add_users.php",
            data: str,
            dataType: 'json',
            cache: false,
            beforeSend: function(html){
                    $('#editbox').html('<img class="preloader" src="images/ajax-loader.gif"/>');
            },

            success: function(html){
                fields = html;
                $('#div1').html(fields['username']);
                $('#div2').html(fields['fname']);

But the divs : #div1 and #div2 will not load the correct data.

FOR WHY?

I assume you have closed the ajax statement correctly? closing both the success function and then the overall ajax function? — Dan Hanly
– Dan Hanly, Commented Mar 15, 2011 at 16:31
yes, they were properly closed, I just included the relevant part of the code — Mazatec
– Mazatec, Commented Mar 16, 2011 at 10:06

Pekka · Accepted Answer · 2010-06-10 11:44:59Z

4

The User Contributed Notes to json_encode have a number of implementations. On a cursory glance, this one looks the best to me.

If you have access to PECL, I would use the extension as @Artefacto recommends.

edited Jun 10, 2010 at 11:44

answered Jun 10, 2010 at 11:28

Pekka

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5 Comments

Mazatec Over a year ago

OK that works fine - firebug shows JSON being passed. However Jquery doesn't like it...

Mazatec Over a year ago

Ok - see the extended question above

Pekka Over a year ago

@Ashley you will need to show some actual JSON so we can tell what's wrong with it. Alternatively, @Mark Baker's suggestion looks interesting as well.

Pekka Over a year ago

@Ashley isn't the JSON result an Object? Meaning you need to use fields.username?

Maxime Pacary Over a year ago

A new implementation has been proposed on User Contributed Notes, seems quite good too. Deserves a try: php.net/manual/en/function.json-encode.php#107968

Bob Fincheimer · Accepted Answer · 2010-06-10 11:28:18Z

1

I hit up the google... This person has made a encoder of their own:

http://www.post-hipster.com/2008/02/15/elegant-little-php-json-encoder/

answered Jun 10, 2010 at 11:28

Bob Fincheimer

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Comments

Artefacto · Accepted Answer · 2010-06-10 11:28:23Z

1

You can use the PECL extension.

answered Jun 10, 2010 at 11:28

Artefacto

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Greg Bacon · Accepted Answer · 2013-03-15 15:51:07Z

0

You can use json_encode for earlier versions of PHP 5.x if you are using an older version of PHP. It works great!

edited Mar 15, 2013 at 15:51

Greg Bacon

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answered Jul 30, 2012 at 15:55

shanmugavel

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