NumberFormatException when converting Integer String in Java

Question

I declare this variable:

private String numCarteBancaireValide=String.valueOf(((Integer.parseInt(Config.NUM_CARTE_BANCAIRE_VALIDE)   ) + (Integer.parseInt("0000000000000001"))));
Config.NUM_CARTE_BANCAIRE_VALIDE is a string.

After Execution, I receive this error message :

java.lang.NumberFormatException: For input string: "4111111111111111"
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.lang.Integer.parseInt(Integer.java:583)
    at java.lang.Integer.parseInt(Integer.java:615)

Please, Can you give your advices ?

Credit Card numbers are not integers and probably should not be treated as such; they are strings, — Alex K.
– Alex K., Commented May 12, 2015 at 12:50

Konstantin Yovkov · Accepted Answer · 2015-05-12 13:06:57Z

4

Use Long.parseLong(), as your parameter is too large for an Integer. (Maximum for an integer is 2147483647)

PS: using Integer.parseInt("0000000000000001") doesn't make much sense either, you could replace this with 1.

edited May 12, 2015 at 13:06

Konstantin Yovkov

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answered May 12, 2015 at 12:49

Tilman Hausherr

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Konstantin Yovkov · Accepted Answer · 2015-05-12 12:50:03Z

1

The 4111111111111111 (which most likely is the value of Config.NUM_CARTE_BANCAIRE_VALIDE) overflows the Integer type.

Better try with:

//if you need a primitive
long value = Long.parseLong(Config.NUM_CARTE_BANCAIRE_VALIDE);

or

//if you need a wrapper
Long value = Long.valueOf(Config.NUM_CARTE_BANCAIRE_VALIDE);

answered May 12, 2015 at 12:50

Konstantin Yovkov

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Rahul Tripathi · Accepted Answer · 2015-05-12 12:51:53Z

1

The maximum value of integer is 2147483647. So you need to use Long.parseLong instead to parse 4111111111111111. Something like this:

long l = Long.parseLong("4111111111111111");

On a side note:

As Alex has commented, if this number is representing a credit card number then you can treat it like a string instead of changing to long as there is no arithmetic calculations involved with the credit card numbers.

answered May 12, 2015 at 12:51

Rahul Tripathi

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Comments

Mena · Accepted Answer · 2015-05-12 12:50:36Z

0

Integer.parseInt will attempt to parse an integer from a String.

Your "4111111111111111" String does not represent an valid Java integer type, as its value would be > Integer.MAX_VALUE.

Use Long.parseLong instead.

answered May 12, 2015 at 12:50

Mena

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