Get the value of array using c# [duplicate]

Question

I got an array

string [] strings = new string[] {"1", "2", "2", "2", "1"};

You can see the value of the array is just 1 and 2, just 2 values, you could say, and I want to get those value out...What I did is here, just a start:

string[] strings = new[] { "1", "2", "2", "2", "1"};
int[] ints = strings.Select(x => int.Parse(x)).ToArray();

I don't what is next...Anyone helps?

I don't what is next? What do you want to do with the extracted int[]? — Yuval Itzchakov
– Yuval Itzchakov, Commented May 13, 2015 at 14:58

Charles Mager · Accepted Answer · 2015-05-13 14:59:06Z

4

You mean you just want an array int[] {1, 2}?

string[] strings = new[] { "1", "2", "2", "2", "1"};
int[] ints = strings.Select(int.Parse).Distinct().ToArray();

answered May 13, 2015 at 14:59

Charles Mager

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MakePeaceGreatAgain · Accepted Answer · 2015-05-13 14:59:18Z

2

You may simply add a distinct to get the unique values:

int[] ints = strings.Select(x => int.Parse(x)).Distinct().ToArray();

Thus your array contains the elements {1, 2}

answered May 13, 2015 at 14:59

MakePeaceGreatAgain

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1 Comment

Eleanor Over a year ago

Nice,,Thanks a lot~~~

user4763353 · Accepted Answer · 2015-05-13 15:01:34Z

1

Classic way:

        string[] strings = new[] { "1", "2", "2", "2", "1" };
        List<int> items = new List<int>();

        for (int i = 0; i < strings.Length; i++)
        {
            int item = int.Parse(strings[i]);

            if (!items.Contains(item))
                items.Add(item);
        }

answered May 13, 2015 at 15:01

user4763353

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