Check a multidimensional array input in javascript

Question

I have an input type hidden in a loop, so it's a multidimensional array and it has one input name.
How can I check if there is any value in it? Like any value or element?

This is the code: (the array is generated in php in a loop)

echo "<td class='$border'>
    <div class='DropZonePers'></div>
    <input type='hidden' value='' name='pers[$dag][$j]'/>
</td>";

What I have tried in js:

if($(".pers").length !> 0) {
   alert("No!");
   return false;
}

How can I do that?

Please remove the "C" tag from this question; it has nothing to do with C. — rost0031
– rost0031, Commented May 13, 2015 at 22:15
@anantkumarsingh dude I can't put the name as a value, the value is created in a drag & drop system — Elomar Adam
– Elomar Adam, Commented May 13, 2015 at 22:25

chiliNUT · Accepted Answer · 2015-05-13 22:31:50Z

2

grab all input elements that have a name that starts with "pers" and see if any are not empty

function persIsEmpty() {
    var empty = true;
    $('input[type="hidden"][name^="pers"]').each(function () {
        if ($(this).val().length > 0 && $(this).val() != '') {
            empty = false;
        }
    });
    return empty;
}

//...so something like

if (persIsEmpty()) {
    alert("No!");
    return false;
}

See: https://css-tricks.com/attribute-selectors/

edited May 13, 2015 at 22:31

answered May 13, 2015 at 22:25

chiliNUT

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Comments

Antonio Dangond · Accepted Answer · 2015-05-13 22:25:55Z

0

$(".pers") searches for an element with class name "pers". Your hidden input does not have that class name. The following will search for the input with type="hidden" and check to see if its value is an empty string.

if ($('input[type="hidden"]').val() == '') {
    alert("No!");
    return false;
}

NOTE: If you have more than one hidden input, and you want to uniquely search for the input specified in your post, give it an id or a unique class to search by.

With class:

$('.className').val()

With ID:

$('#IDName').val()

answered May 13, 2015 at 22:25

Antonio Dangond

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1 Comment

Elomar Adam Over a year ago

I can't do that because some of the input might be empty, the user is not supposed to fill in all the values

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