Getting an Array from Return statement, deduce a string from that

Question

I have a 'Case' conditional code snippet wherein I am returning two objects. The psuedocode is -

case name
when 'a'
object1 = - SQL Logic -
when 'b'
object1 = - SQL Logic -
when 'c'
object2 = - SQL Logic -
when 'd'
object2 = - SQL Logic - 
end
return object1, object2

As evident, I am returning two objects. However, in my Controller I need one object at a time. The object are returned in form of Array like ['value', 'nil']. One of them is always nil. In my controller I am passing one of these objects as -

Model.find_by_sql ["select * from #{object}"]  #either object1 or object2

Is there any way that I can break off this array and return the object that is required at that place as String?

Thanks.

Mihai Dinculescu · Accepted Answer · 2015-06-10 08:11:13Z

1

While you can use compact to eliminate the nil values from your array, I'm not sure why you need this in the first place.

Doing

case name
  when 'a'
    return "SQL statement"
  when 'b'
    return "SQL statement"
  when 'c'
    return "SQL statement"
  when 'd'
    return "SQL statement"
end

is way more intuitive.

edited Jun 10, 2015 at 8:11

answered May 14, 2015 at 17:13

Mihai Dinculescu

20.1k8 gold badges58 silver badges70 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

Niyanta Over a year ago

Can u also explain to me why if I am trying to access one of the returned object, let's say object1 , it single-handedly behaves as an array. like, object1 - ['value', nil] ?

Mihai Dinculescu Over a year ago

It behaves like an array because you return an array. When you return two values, they get put into a single one, an array.

Cary Swoveland Over a year ago

case, not "Case". (Always test!) Consider case name; when 'a','b','c','d' then return "SQL statement"; end or return "SQL statement" if ['a','b','c','d'].include?(name). –

Niyanta Over a year ago

yes thanks for pointing it out..that was actually a Typo..have corrected it now. @CarySwoveland

pangpang · Accepted Answer · 2015-05-14 17:09:43Z

0

return [object1, object2].compact

you can use compact method to remove nil value of array.

answered May 14, 2015 at 17:09

pangpang

8,86915 gold badges67 silver badges99 bronze badges

Comments

Cary Swoveland · Accepted Answer · 2015-06-09 18:25:03Z

0

You could write:

return (['a', 'b'].include?(name) && - SQL Logic 1 -) ||
         (['c', 'd'].include?(name) && - SQL Logic 2 -)

If it's the last line of a method, you don't need return.

Let's see what's happening.

If ['a', 'b'].include?(name) #=> true, - SQL Logic 1 -, which is truthy, will be returned.

If ['a', 'b'].include?(name) #=> false, the first && clause is false (- SQL Logic 1 - is not executed), so we consider the other || clause. ['c', 'd'].include?(name) must be true, so we return - SQL Logic 2 -.

answered Jun 9, 2015 at 18:25

Cary Swoveland

111k6 gold badges69 silver badges105 bronze badges

Collectives™ on Stack Overflow

Getting an Array from Return statement, deduce a string from that

3 Answers 3

4 Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

4 Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related