Javascript Replace using Regex

Question

I want to replace start from @ to º with 0 below is my string

I try its working only for 2 pair but not working for 3 etc pair

Example 01:

Input Data

@8~Cº + @9~Cº

Output

0 + 0

Example 02:

Input Data

@11~Cº + @12~P1º - @13~Fº

Output

0+0+0

Below is my code

var tempRes = "@11~Cº + @12~P1º - @13~Fº";
tempRes = tempRes.replace(/@[0-9]~[A-Z]º/i,parseFloat(0));

In one output, you have spaces; in the other, you don't -- but there are spaces in both inputs. Do you want them or not? — T.J. Crowder
– T.J. Crowder, Commented May 18, 2015 at 10:15
Okay. Please use the "edit" link to correct the question. Please also note the formatting fixes I applied for you: Taking the time to make sure your question is clearly formatted is important. There's an entire toolbar full of things to help you, and a lot of help available from the [?] button. — T.J. Crowder
– T.J. Crowder, Commented May 18, 2015 at 10:18

anubhava · Accepted Answer · 2015-05-18 10:18:57Z

3

You can do:

var s = '@11~Cº + @12~P1º + @13~Fº'
var r = s.replace(/@[^º]+º/g, 0);
//=> 0 + 0 + 0

EDIT: To remove spaces also

var r = s.replace(/\s*@[^º]+º\s*/g, 0);
//=> 0+0+0

edited May 18, 2015 at 10:18

answered May 18, 2015 at 10:12

anubhava

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Wiktor Stribiżew · Accepted Answer · 2015-05-18 10:22:11Z

0

I would use this regex in case you have multiple lines in your input:

[ ]*@[^º\n]*º[ ]*

See demo

Explanation:

[ ]* - Optional space(s)
@ - A @ symbol
[^º\n]* - 0 or more symbols other than º and a line break
[ ]* - Optional space(s)

answered May 18, 2015 at 10:22

Wiktor Stribiżew

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Nader Hisham · Accepted Answer · 2015-05-18 10:22:43Z

0

you can use this regular expression to catch what you want

@.+?º

try this demo

Demo

to remove spaces use this regex

\s*@.+?º\s*

try this Demo

var input = '@11~Cº + @12~P1º + @13~Fº'
var output = input.replace(/\s*@.+?º\s*/g, 0)

edited May 18, 2015 at 10:22

answered May 18, 2015 at 10:15

Nader Hisham

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