Php/Html form with different option selection

Question

my php and html coding is:

$damt2 = isset($_POST['damt2']) ? $_POST['damt2'] : 200;
$dateinfo2 = json_decode(file_get_contents($_SESSION['base_path'] . 'dl.dict'), true);
arsort($dateinfo2); //arsort — Sort an array in reverse order and maintain index association
$dateinfo2 = array_slice($dateinfo2, 0, $damt2); //array_slice — Extract a slice of the array

Table

<input type="hidden" name="userId" value="<?= $_SESSION['userId']; ?>">
<select name="damt2" onchange="this.form.submit()">
<option value="50" <?= (isset($damt2) & $damt2 == 50) ? 'selected' : ''; ?>>50</option>
<option value="100" <?= (isset($damt2) & $damt2 == 100) ? 'selected' : ''; ?>>100</option>
<option value="200" <?= (isset($damt2) & $damt2 == 200) ? 'selected' : ''; ?    >>200</option>

<input name="radio" type="radio" value="cow">Cow
<input name="radio" type="radio" value="chicken">Chicken
</select>  <input type="submit" name="submit" value="Show List & Save">

<?php    
    foreach ($dateinfo2 as $key => $time){
    $uInfo = $_SESSION['data']->table('units')->byName($key)->data();
    if ($uInfo["keyword"] != 'chicken') continue;
    if ($uInfo["keyword"] != 'cow') continue;
    if (isset($uInfo['type']) && !empty($uInfo['type'])) {
        echo '<center><font color="olive">TypE: '.$uInfo['type'].'</font><br>';
    }else{
    }
}
?>

Why in results all blank ?

I guess where i'm doing mistake : In foreach loop by both values are continued. In category selection with radio button.

I want form with two options ( one with search number 50,100,200 ) and second with category like " cow " and " chicken " .

Please use <?php instead of <?. if you use <? php.ini --->short_opentag=On — odedta
– odedta, Commented May 18, 2015 at 12:00
Add error reporting to the top of your file(s) right after your opening <?php tag error_reporting(E_ALL); ini_set('display_errors', 1); — Jay Blanchard
– Jay Blanchard, Commented May 18, 2015 at 12:02
yes session starts again ! and please have a look what my table is showing in results . prntscr.com/76kabe — Fake
– Fake, Commented May 18, 2015 at 12:10
Just asking ( don't know if this one is suitable ) " if(!isset($_POST['cow'])){ if ($uInfo["keyword"] != 'cow') continue; } " how to use it ? @JayBlanchard — Fake
– Fake, Commented May 18, 2015 at 13:04

Fake · Accepted Answer · 2015-05-18 17:07:51Z

3

My question is solved now and i did it by reading several posts from all around the internet and at the end i tried :

IN HTML section:

<input name="cow" type="radio" >Cow
<input name="chicken" type="radio" >chicken

PHP coding :

<?php
 foreach ($dateinfo2 as $key => $time)
{
  $uInfo = $_SESSION['data']->table('units')->byName($key)->data();//item get data by name

  if(isset($_POST['cow'])){
    if ($uInfo["keyword"] != 'cow') continue;
}
  if(isset($_POST['chicken'])){
    if ($uInfo["keyword"] != 'chicken') continue;
}
if (isset($uInfo['type']) && !empty($uInfo['type'])) {
    echo '<center><font color="olive">TypE: '.$uInfo['type'].'</font><br>';
}else{
 }
}

In the results, i have two radio buttons and pulldown menu to select length(50,100,200..etc) of result with desire category (Chicken/Cow). thank you all for trying to support me with your suggestions. Have good day to all ^_^

answered May 18, 2015 at 17:07

Fake

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1 Comment

Aryan Aly Over a year ago

helpful for me too @Fake

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