HTML & PHP uploader doesn't work

Question

I am playing with an uploader on PHP. Basically, I did a simple one just for echoing what is chosen from submit button for right now.

<? php
echo $name  = $_FILES['file]['name'];

?>

<form action="upload.php" method="POST" enctpe="multipart/form-data">

<input type ="file" name="file"> <br> <br>
<input type="submit" value ="Submit">

</form>

I am using xampp and where I located this file is in a folder in htdocs. apache is running, PHP is running without hesitating whenever I refresh

http://localhost:81/phpex/upload.php

It just doesn't work and not echoing choosen file name.

Can you tell me what, actually, is wrong with it?

Can you please post the contents of phpex/upload.php? And is this page in the phpex directory? — Ben
– Ben, Commented May 19, 2015 at 13:26
Firstly, you have syntax error $_FILES['file]['name'];. Secondly: remove action="upload.php" — Kristiyan
– Kristiyan, Commented May 19, 2015 at 13:27
@Kristiyan ok fixed it still not working...secondly without defining action how it is supposed to pass submission into php paragraph? — gobo
– gobo, Commented May 19, 2015 at 13:30
Add error reporting to the top of your file(s) right after your opening <?php tag error_reporting(E_ALL); ini_set('display_errors', 1); — Jay Blanchard
– Jay Blanchard, Commented May 19, 2015 at 13:30

Kristiyan · Accepted Answer · 2015-05-19 13:49:27Z

2

Misspelling in your HTML: enctpe must be enctype.

Also I told you for syntax error echo $name = $_FILES['file']['name'];

Edit: Already tested:

<?php
if(isset($_POST)){ // prevent notice.
echo $name  = $_FILES['file']['name'];
}
?>
<form method="POST" enctype="multipart/form-data">
<input type ="file" name="file"> <br> <br>
<input type="submit" value ="Submit">
</form>

edited May 19, 2015 at 13:49

answered May 19, 2015 at 13:32

Kristiyan

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8 Comments

Kristiyan Over a year ago

@gobo, I've just edited my answer. You've wrong opening <?php tag. Please just copy/paste my code.

gobo Over a year ago

yours throws error Notice: Undefined index: file in C:\xampp\htdocs\phpex\upload.php on line 2

Kristiyan Over a year ago

Your code return it. Upload file and it will work. I've change it.

Jay Blanchard Over a year ago

That is because there is no test to see if $_FILES is set before assigning the variable.

gobo Over a year ago

@JayBlanchard after I fixed syntax <?php //error_reporting(E_ALL); ini_set('display_errors', 1); echo $name = $_FILES['file']['name']; ?> <form action="upload.php" method="POST" enctype="multipart/form-data"> <input type ="file" name="file"> <br> <br> <input type="submit" value ="Submit"> </form> it gives an error as( ! ) Notice: Undefined index: file in C:\xampp\htdocs\phpex\upload.php on line 3

|

Ben · Accepted Answer · 2015-05-19 13:27:55Z

0

echo $name  = $_FILES['file]['name'];

should be

echo $name  = $_FILES['file']['name'];

- you missed out a quotation mark.

answered May 19, 2015 at 13:27

Ben

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2 Comments

SaidbakR Over a year ago

What is the difference between the two lines?

Ben Over a year ago

['file'] vs ['file]

Youssef · Accepted Answer · 2015-05-19 14:02:18Z

0

have to show array _files to see all properites : var_dump($_FILES) ;

your code is correct i think just change name of file

 <input name="photo" type="file" id="photo" />


 <?php $photo=$_FILES["photo"]["name"];
    echo $photo ;
 ?>

answered May 19, 2015 at 14:02

Youssef

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