PHP RegEx - Get All Digits

Question

I have this code:

$string = "123456ABcd9999"; 
$answer = ereg("([0-9]*)", $string, $digits); 
echo $digits[0];

This outputs '123456'. I'd like it to output '1234569999' ie. all the digits. How can I achieve this. I've been trying lots of different regex things but can't figure it out.

ircmaxell · Accepted Answer · 2010-06-14 17:45:00Z

15

First, don't use ereg (it's deprecated). Secondly, why not replace it out:

$answer = preg_replace('#\D#', '', $string);

Note that \D is the inverse of \d. So \d matches all decimal numeric characters (0-9), therefore \D matches anything that \d does not match...

answered Jun 14, 2010 at 17:45

ircmaxell

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Lauri Lehtinen · Accepted Answer · 2010-06-14 17:43:13Z

7

You could use preg_replace for this, preg_replace("/[^0-9]/", "", $string) for example.

answered Jun 14, 2010 at 17:43

Lauri Lehtinen

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