If I have a String,
String x = "10 20 30 40";
Is there any way to convert it into an int array like this?
int[] y = {10, 20, 30, 40};
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Is there any built-in method in java that can do this?Sajid– Sajid2015-05-22 19:11:43 +00:00Commented May 22, 2015 at 19:11
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4 Answers
In a functional way, using Java 8 streams:
int[] y = Arrays.stream(x.split(" ")).mapToInt(Integer::parseInt).toArray();
Comments
int[] convert(String x){
String[] val = x.split(" ");
int[] arr = new int[val.length];
for (int i = 0; i < val.length; ++i){
arr[i] = Integer.parseInt(val[i]);
}
return arr;
}
3 Comments
Bacteria
It should not be int[] arr = new int[val.size];, it should be int[] arr = new int[val.length]; I hope this is a type.
Shantanu Deshpande
Sorry about the typo. The loop had val.length
nhgrif
This answer could be improved if you made more of an effort to explain what was going on in this code so that the asker has more of a hope of understanding it. I'm not a very big fan of "gimmeh teh codez" questions being rewarded with "gimmeh teh codez" answers.
Maybe something like this, to get you started with your assignment :)? Using Strings split method with regular expressions.
String x = "10 20 30 40";
String[] cut = x.split(" ");
Now you have an array in cut. Then you'll need to loop through that and get the Integer value of the Strings, and do whatever more you need to..
happy coding!
1 Comment
MRK187
why was this downvoted its not wrong, you should make your research instead of posting you assignments here
You can combine the functions like the c++
find(character,range)
and
substring(initial position,range)
and a counter to increment the initial position
to create a vector with the elements as srting
and finally parse all the elements to the int type
(i didn know how to do that in java)
1 Comment
Jesper
The question is about Java - if you don't know how to do it in Java, you'd better not answer the question. How to do it in C++ is not useful for the person who asked the question.