not getting value with push array

Question

In the following AJAX function, I'm trying to implement push array. There is problem with that array: I am not getting that array value in post in alert I am getting that value in array but when passing that value it's undefined.

  <script type="text/javascript">

  function getmember()
  {
    var myarray = new Array();
    myarray.push($(".group_id").val());
    alert(myarray);
     $.ajax({
      type: "GET",
      url: "getmember.php", 
      data: myarray,
      success: function(data) {
        $(".the-return").html(
          "Favorite beverage: " + data["favorite_beverage"] + "<br />Favorite restaurant: " + data["favorite_restaurant"] + "<br />Gender: " + data["gender"] + "<br />JSON: " + data["json"]
        );

        alert("bb");
      }
    });
    return false;
  } 
  </script>

<select name="group_id" class="group_id" onChange="getmember();" multiple>

             <?php
               $selectGroup = "SELECT group_id,group_name FROM `group`";
               $groupRes           = mysql_query($selectGroup);
               while($row1 =  mysql_fetch_array($groupRes))
               {
                 echo '<td><option value="'.$row1['group_id'].'">'.$row1['group_name'].'</option></td>';
               }
             ?>
          </select>

Do you mean the alert(myArray) shows nothing? can you show the HTML for .group_id? — AmmarCSE
– AmmarCSE, Commented May 25, 2015 at 11:02
Some punctuation in your prose would really help to make it understandable. I've added some where I could figure it out, but there's more missing after I am not getting where I'm not sure what you meant. — das-g
– das-g, Commented May 25, 2015 at 11:14

Nishit Maheta · Accepted Answer · 2015-05-25 11:54:23Z

1

push value with key and define variable myarray as global

   var myarray; 
   function getmember()
   {
     myarray = [];
     myarray.push({'group_id':$(".group_id").val()});
    // your code.
   }

as discussed to post data like below URL

http://localhost/ashutosh/getmember.php?group_id=1,2,3,4

UPDATED CODE:

 var myarray;
 function getmember()
 {
   myarray = [];
   myarray.push($(".group_id").val());
   // your code.

    url: "getmember.php", 
    data:'group_id='+myarray.join(),
 }

edited May 25, 2015 at 11:54

answered May 25, 2015 at 11:27

Nishit Maheta

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9 Comments

Prashant Bhatt Over a year ago

now i want to used this id in select query what should i do for it me implode that in my php file or that is possible with something else

Nishit Maheta Over a year ago

chat option is block at my work place see this example tutorialspoint.com/mysql/mysql-in-clause.htm

Nishit Maheta Over a year ago

SELECT * FROM your table WHERE group_id IN ( 1,2,3 );

Prashant Bhatt Over a year ago

suppose if i am selecting one value after that i am selecting another value than it pass first value two time..

Prashant Bhatt Over a year ago

my select query is like this $group_id = $myarray[]; $selectGroup = "SELECT contact_id FROM addressgroup WHERE group_id IN($group_id)";

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