How can I return json from my specific sql query?

Question

I have the following php code:

<?php
$servername = "host";
$username = "user";
$password = "passw";
$dbname = "dbname";

$conn3 = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);

$conn3->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

$q3 = $conn3->prepare("SELECT c.one, c.two FROM table c");
    $q3->execute();
if($q3->rowCount()>0)
{
    $check3 = $q3->fetchAll(PDO::FETCH_ASSOC);
    $arr = array();
    foreach ($check3 as $row) {
    $arr[] = $row;
     //how can I return json format here?
    }   
}
$conn2 = null;
?>

and this query returns pairs of elements. But how can I modify the code above to get the json format of the elements as:

{key1:OSO;key2:AIKA} etc.

so that I can use it later in a jquery file to print it with the following fuction:

$.getJSON('list.php', function(json) {
    //assuming list.php resides with list.html directory
    //console.log(json)
      console.log(json.result.key1);
       console.log(json.result.key2);

    });

thanks!

Alex Tartan · Accepted Answer · 2015-05-25 21:51:35Z

2

Change

SELECT c.one, c.two FROM table c

to

SELECT c.one as key1, c.two as key2 FROM table c

Then encapsulate the results in json (after the foreach):

echo json_encode(array(
    'result'=>$arr
));

But you will most likely need to loop trough them in jquery.
Your json output will be something like:

result: [
    {'key1': 'asd', 'key2': 'qwe'},
    [...]
    {'key1': 'asd', 'key2': 'qwe'}
]

Loop trough them like:

//first, see how it looks:
console.log(json.result);
jQuery.each( json.result, function( i, subresult ) {
    console.log(subresult);
    // you should be able to use: subresult.key1
});

edited May 25, 2015 at 21:51

answered May 25, 2015 at 21:02

Alex Tartan

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4 Comments

randomuser1 Over a year ago

hey thanks, could you give me some example of how to loop through them in jquery then? thanks!

randomuser1 Over a year ago

Thanks, I did

if($q3->rowCount()>0) { 	$check3 = $q3->fetchAll(PDO::FETCH_ASSOC); 	$arr = array(); 	foreach ($check3 as $row) { 	$arr[] = $row; 	} 	 	echo json_encode(     'result'=>$arr ); }

but now I get the error Parse error: syntax error, unexpected T_DOUBLE_ARROW and I'm not sure what's the problem here :|

Alex Tartan Over a year ago

My bad. It's json_encode(array('result'=>$arr)); I'm on my phone

randomuser1 Over a year ago

Hey @Alex, thanks for your dedication though! Your solution worked!

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