swift - Initializing another class inside a class?

Question

Hello everybody I am a beginner in programing FYI! This is the problem that I have: I have two classes: Human and Pet. The Pet class has a method called eat that prints a simple "eat" line. The Human class has a method that calls the eat method from the Pet class. The way I am trying to implement this is by creating a Pet object inside the Human class so that a Human method can call the Pet methods.

Is this a right way to go about this? I'm also running into problems attempting to create the Pet inside Human...

This is what I have so far:

class Human{
var humanName: String
var Pet = Pets(petName: String, noise: String, canMakeNoise: Bool)

init(humanName: String, petName: String, noise: String, canMakeNoise: Bool){
    self.humanName = humanName

func feedPet(){
        //insert Feed function here
    }

class Pets{
var petName: String
var noise: String
var canMakeNoise: Bool

init(petName: String, noise:String, canMakeNoise:Bool){
    self.petName = petName
    self.noise = noise
    self.canMakeNoise = canMakeNoise
}

func eat(){
    println("\(self.petName) is eating...")
}

Thank you!

ridvankucuk · Accepted Answer · 2015-05-27 17:51:44Z

3

change this line:

var pet = Pets(petName: String, noise: String, canMakeNoise: Bool)

to this line:

var pet: Pets?

And after that you can create an instance of your Human class such as:

var human = Human(humanName: "chris", petName: "abc", noise: "hi", canMakeNoise: true)
var dog = Pets(petName: "erty", noise:"bark", canMakeNoise:true)
human.pet = dog

edited May 27, 2015 at 17:51

answered May 27, 2015 at 17:45

ridvankucuk

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4 Comments

Michael Ninh Over a year ago

Thanks for the reply! I did var pet = pets? but now its complaining, "Expected member name or constructor call after type name"

ridvankucuk Over a year ago

Sorry i have edited my answer. You should use var pet: Pets?

Michael Ninh Over a year ago

it worked! thank you so much, been stuck here forever!

Ali Beadle Over a year ago

@MichaelNinh As it helped, please mark ridvankucuk's answer as correct (click the tick).

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