I want to define a function, to find out the index of a list which satisfies some condition. But it always have some error：
TypeError: 'int' object is not iterable
Below is my code
def find_index(x,*arr):
for i in len(arr):
if abs(i-x) < 1e-5:
j = arr.index(i)
return j
How do I specify arr is a list or numpy array? (Sorry, I do not know how to format the code in this editor)
Thanks a lot.
The (first) problem is for i in len(arr). len(arr) returns an integer which isn't iterable. You might be tempted to use a range(len(arr)), but don't give in. There are better options! We can keep track of the index of the value as we iterate. Generally, this function would probably look something like:
def find_index(x, arr):
for i, val in enumerate(arr):
if abs(val - x) < 1.e-5:
return i
Now you can call this on any iterable. e.g.:
find_index(5, [1, 2, 3, 5, 60]) # passing a list
find_index(5, (0, 5+1e-6, 10)) # passing a tuple
enumerate: arr.index(i) is wasteful if you just want to know the index of the already found element.
I think you would want to replace
for i in len(arr)
with:
for i in range(len(arr))
You can Try to like :
l=len(arr)
for i in range(l)
i returns is integer value .integer value not iterable.
