Extracting specific parts of a HTML-File with PHP Simple HTML DOM Parser

Question

I've got a HTML-File with several tables from which I try to extract the link and image part. I'm using the PHP Simple HTML DOM Parser.

Here's the HTML-File to parse:

<h1>Title</h1>
<p>Text</p>

<table cellspacing="0" cellpadding="0" border="0">
    <tbody>
        <tr><td>
            <a href="http://www.google.com/some_url">
                <img width="100" height="100" border="0" src="http://google.com/some_image.jpg"/>
            </a>
        </td></tr>
    </tbody>
</table>

<h2>Title</h2>
<p>Text</p>

<table cellspacing="0" cellpadding="0" border="0">
    <tbody>
        <tr><td>
            <a href="http://www.google.com/this_url">
                <img width="100" height="100" border="0" src="http://google.com/this_image.jpg"/>
            </a>
        </td></tr>
    </tbody>
</table>

<p>Text</p>
<p>Text</p>

And what I need as an output:

<a href="http://www.google.com/some_url">
    <img width="100" height="100" border="0" src="http://google.com/some_image.jpg"/>
</a>

<a href="http://www.google.com/this_url">
    <img width="100" height="100" border="0" src="http://google.com/this_image.jpg"/>
</a>

Here's the PHP part – but doesn't work the way i want it...

<?php

// Include the library
include('simple_html_dom.php');

// Retrieve the DOM from a given URL
$html = file_get_html('http://google.com');

// Find all images & links
foreach($html->find('img') as $IMGelement)
foreach($html->find('a') as $Aelement)
echo '<a href="' . $Aelement->href . '"><img src="' . $IMGelement->src . '" /><br>';

?>

Where are you using the PHP Simple HTML DOM Parser? I don't see it, looks like HTML. I also don't see a question here about the issue you are having with the parsing. — chris85
– chris85, Commented May 29, 2015 at 20:11
Please find the PHP code above. But it's not really working the way i want it... — Corrupt Network
– Corrupt Network, Commented May 29, 2015 at 20:46
Okay, and what happens with the current code vs. what do you want to happen? — chris85
– chris85, Commented May 29, 2015 at 20:47
Current code generates a list of every picture with every link. What i want is to extract the link and image only out of each table. In the HTML-Code above commented as "". — Corrupt Network
– Corrupt Network, Commented May 29, 2015 at 20:52

TripleDeal · Accepted Answer · 2017-05-30 18:30:43Z

1

I think you want to find an img within a tag :

foreach($html->find('a img') as $IMGelement) {
    echo '<a href="' . $IMGelement->parent()->href . '"><img src="' .$IMGelement->src .'" /><br>';
}

edited May 30, 2017 at 18:30

TripleDeal

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answered May 29, 2015 at 21:31

splash58

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11 Comments

Corrupt Network Over a year ago

This generates a list of all images, but without the link inside the "a href"-tag...

splash58 Over a year ago

@CorruptNetwork $IMGelement->parent()->href show the link very well

Corrupt Network Over a year ago

Yes, this works! Thanks a lot! Is there also a way to extract only the images/links within the specific tables? i have a lot of other HTML-stuff in that file i don't need (see HTML above).

splash58 Over a year ago

@CorruptNetwork Write a condition to select, I try. By the way, it would be good to accept the answer

splash58 Over a year ago

Glad to help! And what about your additions?

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