Powershell variable in replacement string with named groups

Question

The following Powershell replace operation with named groups s1 and s2 in regex (just for illustration, not a correct syntax) works fine :

$s -Replace "(?<s1>....)(?<s2>...)" '${s2}xxx${s1}'

My question is : how to replace with a variable $x instead of the literal xxx, that is, something like :

$s -Replace "(?<s1>....)(?<s2>...) '${s2}$x${s1}'

That doesn't work as Powershell doesn't replace variable in single quoted string but the named group resolution doesn't work anymore if replacement string is put in double quotes like this "${s2}$x${s1}".

Thanks, works perfectly ! It really makes sense when you have the answer ;-) — user957479
– user957479, Commented May 31, 2015 at 12:09

Vincent De Smet · Accepted Answer · 2015-05-30 12:03:54Z

4

@PetSerAl comment is correct, here is code to test it:

$sep = ","
"AAA BBB" -Replace '(?<A>\w+)\s+(?<B>\w+)',"`${A}$sep`${B}"

Output: AAA,BBB

Explanation:

Powershell will evaluate the double quoted string, escaping the $ sign with a back tick will ensure these are not evaluated and a valid string is provided for the -Replace operator.

or via Get-Help about_escape & Get-Help about_comparison_operators

edited May 30, 2015 at 12:03

answered May 30, 2015 at 11:40

Vincent De Smet

4,9992 gold badges38 silver badges42 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Ransom Over a year ago

You are the reason i still have hair on my head man. Thank you for this!

Collectives™ on Stack Overflow

Powershell variable in replacement string with named groups

1 Answer 1

1 Comment

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Linked

Related