Concat array and string variable for value [duplicate]

Question

I have a variable $temp which contains:

['test1']['test2']['test3']

I want to get the value of this variable in an array : $array.
I tried $array[$temp] and other possibilities.

getNavItemIndex returns an array containing the position of the value asked

Edit:

$input = array();
$input['level0']['level1']['somekey'] = "value of somekey";
$input['level0']['level1']['somekey2'] = "value of somekey2";
$input['level0']['level1b']['somekey1b'] = "value of somekey1b";
$input['level0']['level1']['level2']['somekey1c'] = "value of somekey1c";
$json1 = getNavItemIndex($input, "value of somekey1c");  
foreach ($json1 as $key => $value) {
    $temp .= "['";
    $temp .= $value; 
    $temp .= "']";   
}
echo $temp; // ['level0']['level1']['level2']['somekey1c']
echo $input[$temp]; //value of somekey1c

Should it look like $temp[0]='test1',$temp[1]='test2' & $temp[2]='test3' ? — Tristup
– Tristup, Commented Jun 2, 2015 at 9:05
I have edited, i want this expected output : value of somekey1c — Thibaut Silva
– Thibaut Silva, Commented Jun 2, 2015 at 9:11

Karl · Accepted Answer · 2015-06-02 09:44:16Z

0

Changed the answer after your edit.

$output = null;
for($i = 0; $i < count($temp); $i++) {
    if($output === null && isset($input[$temp[$i]])) {
        $output = $input[$temp[$i]];
    }elseif (isset($output[$temp[$i]])) {
        $output = $output[$temp[$i]];
    }else {
        $output = null;
    }
}
echo $output;

You also need to edit your code when you are creating the temp array.

$temp = [];
foreach ($json1 as $key => $value) {
    $temp[] = $value;   
}

Update A more eloquent and reusable solution.

function getByKeys($arr, $keys) {
    $key = array_shift($keys);
    if(isset($arr[$key])) {
        if(count($keys) > 0) {
            return getByKeys($arr[$key], $keys);
        }else {
            return $arr[$key];
        }
    }else {
        throw new Exception('Key is not isset');
    }
}

echo getByKeys($input, $temp);

edited Jun 2, 2015 at 9:44

answered Jun 2, 2015 at 9:07

Karl

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2 Comments

Thibaut Silva Over a year ago

I was looking for more simple but it works thank you :)

Karl Over a year ago

I think the new solution would be a little more simple, aslo it's more reusable :)

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