How can i achieve something like this in for loop in ruby:
for(int i = 1;i<=10;i++){
if (i == 7){
i=9;
}
#some code here
}
I meant to say it's okay to use "next" to skip but what to do if I want to just jump to an uncertain iteration via changing the variable value itself. As far as I know loop works with enumerable type. I want to loop it via index as a variable, the way we do in C++
The most accurate answer to your question would be to use a while loop, like this:
i = 0
while i < 10
if i == 0 # some condition
i = 9 # skip indexes
else
i += 1 # or not
end
end
There are few things you can do:
Incase you want to skip a few iterations based on a defined logic, you can use:
next if condition
If your intention is to randomly iterate over the whole range, you can try this:
(1..10).to_a.shuffle.each { |i|
# your code
}
Incase you want to randomly iterate over a certain chunk of given range, try this:
(1..10).to_a.shuffle.first(n).each { |i| # n is any number within 1 to 10
# your code
}
How about this?
array = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15]
array.each_with_index do |elem, idx|
break if idx == 9
# do something
puts "element #{idx} with #{elem}"
end
Why not a recursive approach ? like
foo(x)
{
if x == 7
{
return foo(9)
}
return foo(x+1)
}
(1..10).each do |i|
next if(i == 7 || i == 8)
# some code here
end
