PHP : How to set array Value with $_GET

Question

i tried to set the value of the $_GET[] into an array object

this is my code

$X=array(
'status_1'=>'"'.$_GET['hasil_1'].'"',
'status_2'=>'"'.$_GET['hasil_2'].'"',
'status_3'=>'"'.$_GET['hasil_3'].'"',
.
.
'status_17'=>'"'.$_GET['hasil_17'].'"');

//Faktor Klasifikasi
$n = 'derajat';

//nama tabel
$table='tabel';

classify($X,$n,$table);

it's not working .

this is the url

http://localhost:8080/tugas/sispak/hasil.php?hasil_1=1&hasil_2=1&hasil_3=1&hasil_4=1&hasil_5=1&hasil_6=0&hasil_7=1&hasil_8=1&hasil_9=0&hasil_10=1&hasil_11=1&hasil_12=1&hasil_13=1&hasil_14=1&hasil_15=1&hasil_16=1&hasil_17=1

but , if i write it manualy like

$Y=array(
'status_1'=>'1',
'status_2'=>'1',
'status_3'=>'1',

.
.
'status_17'=>'1'
);

it works !!

this is where I handle the values of my array

//var_dump($allclass);
    foreach($allclass as $c=>$p)
    {
        foreach($X as $x=>$y)
        {
            $i = mysql_query("select count(*) as num from ".$table." where ".$n."='".$c."' AND ".$x."='".$y."'");
            $j = mysql_fetch_array($i,MYSQL_ASSOC);

            $P[$c][$x] = round($j["num"]/$allclass[$c],2);

    //Exception: P(data/class) might be 0 in some cases, ignore 0 for now
            if($P[$c][$x] != 0)
                $argmax[$c] *= $P[$c][$x];
        }
        $argmax[$c] *= $Pc[$c];
    }

somebody help me ,please

"it's not working" Never think that this is an acceptable problem description. And if you'd just printed out your MySQL query you'd have seen the problem...... — Lightness Races in Orbit
– Lightness Races in Orbit, Commented Jun 2, 2015 at 18:41

taxicala · Accepted Answer · 2015-06-02 18:25:19Z

4

You dont need all those quotes, try as follows:

$X = array(
    'status_1'=> $_GET['hasil_1'],
    'status_2'=> $_GET['hasil_2'],
    'status_3'=> $_GET['hasil_3']
);

answered Jun 2, 2015 at 18:25

taxicala

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