Breaking out of a for loop from a nested if statement in Django

Question

is there a way to break out of this for loop from inside the if statement. Currently our database is incorrectly storing multiple primary phones and I would like to break out of the for loop after the first primary phone is found. Thank you in advance for any help.

{% for phone in user_phones %}
    {% if phone.primary %}
        <div>{% if phone.type %}{{ phone.type|title }}: {% endif %}<span itemprop="telephone">{{ phone.phone_format }}</span></div>
    {% endif %}
{% endfor %}

Updated:

Or just fail the if condition by creating a variable within the if true branch

possible duplicate of How to break "for loop" in Django template — Wtower
– Wtower, Commented Jun 2, 2015 at 19:19
This sounds more like business logic than a ui/template problem. I recommend preparing a specific context variable in your view. — timo.rieber
– timo.rieber, Commented Jun 2, 2015 at 19:26

sthzg · Accepted Answer · 2015-06-04 14:46:51Z

If you have to stay within the template layer you could use regroup.

{% regroup user_phones|dictsort:"primary" by primary as phones_list %}

{% for phone in phones_list %}
    {% if phone.grouper %}
    {{ phone.list.0.type }}
    {% endif %}
{% endfor %}

What it does

regroup together with the dictsort filter (which also works on querysets) groups the instances in user_phones by the value of primary.

regroup will add an attribute named grouper, which when grouping by a bool (the value of primary) will either be True or False.

for then iterates over the variable phones_list, which is provided by regroup. Since we have sorted the results by primary, {% if phone.grouper %} will tell us when we hit the group of items with primary == True.

regroup packs the items that belong to a group into the attribute list. So the first item can be accessed with phone.list.0.type, phone.list.0.phone_format, etc.

Note:
if you need to access foo.list.0 many times it can be assigned to a variable (using with):

{% regroup user_phones|dictsort:"primary" by primary as phones_list %}

{% for items in phones_list %}
    {% if items.grouper %}
    {% with items.list.0 as phone %}
    <div>{% if phone.type %}{{ phone.type|title }}: {% endif %}<span itemprop="telephone">{{ phone.phone_format }}</span></div>
    {% endwith %}
    {% endif %}
{% endfor %}

malisit · Accepted Answer · 2015-06-02 19:28:00Z

0

There is no break in Django templates. You may handle it in your view by storing the primary phone that you are looking for to a variable and then calling it in your template.

answered Jun 2, 2015 at 19:28

malisit

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5 Comments

Dusty Over a year ago

So there's no way to do it from inside the if statement?

mipadi Over a year ago

@Dusty: No, break is not possible in a Django template for loop. You'll have to process the data before passing it to the template.

malisit Over a year ago

@Dusty yes, there is no way. You should handle it in views.py.

Dusty Over a year ago

Can you define variables in for loops in Django?

malisit Over a year ago

You cannot. You should do it in py file.

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