How to store selected multiple checkbox values in an array in php?

Question

<input type="checkbox"name="travel[]" value="bus"/>
<input type="checkbox"name="travel[]" value="train"/>
<input type="checkbox"name="travel[]" value="plane"/>
foreach($_POST['travel']as $selected)
  var select[]=$selected;

If the user selects all the three checkboxes, I have to store them in an array and send it to mail as I dont have a data base. So how should I store them in an array?

foreach($_POST['travel']as $selected)
var select[]=$selected;

The above code is returning only last selected check box And how should I pass it and display it on the mail?

No need of foreach because your $_POST['travel'] is itself an array with that 3 selected value use that directly.thanks. — Death-is-the-real-truth
– Death-is-the-real-truth, Commented Jun 4, 2015 at 7:24
There should be a space between checkbox"name. $html='You selected '; foreach($_POST['travel']as $selected) $html.=$selected." "; — Jobst
– Jobst, Commented Jun 4, 2015 at 7:28
I am not sure you excpeted this is var select = implode(",",$_POST['travel']); now you get the value using {{select}} in mail template its returns bus,train — Sathish
– Sathish, Commented Jun 4, 2015 at 7:31
Thank you sathish. what is the difference between var selcet and $select?can I use $select = implode(",",$_POST['travel']); — raga
– raga, Commented Jun 4, 2015 at 7:57

Narendrasingh Sisodia · Accepted Answer · 2015-06-04 08:37:07Z

3

Instead of

foreach($_POST['travel']as $selected)
var select[]=$selected;

update it to

$select = array();
foreach($_POST['travel'] as $key => $selected){
    $select[$key]=$selected;
}

Instead of using foreach simply use $select = implode(',',$_POST['travel']);

edited Jun 4, 2015 at 8:37

answered Jun 4, 2015 at 7:24

Narendrasingh Sisodia

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2 Comments

Death-is-the-real-truth Over a year ago

it is correct answer. why down-voted.? people are insane. i up-voted to you.

Narendrasingh Sisodia Over a year ago

Even I don't know whats the reason behind the downvoting. Anyways thanks @anantkumarsingh

Viral · Accepted Answer · 2015-06-04 07:25:10Z

0

Because every time you are defining a new array, by var select[]=$selected;.

Change it it $select[]=$selected;

answered Jun 4, 2015 at 7:25

Viral

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Comments

Kshitij Soni · Accepted Answer · 2015-06-04 07:50:36Z

0

please give different names as below. after posting data using foreach loop you will get all selected options <input type="checkbox" name="travel1[]" value="bus"/> <input type="checkbox" name="travel2[]" value="train"/> <input type="checkbox" name="travel3[]" value="plane"/>

answered Jun 4, 2015 at 7:50

Kshitij Soni

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