PHP foreach loop - need different value from text shown

Question

I have a simple foreach loop as follows:

foreach ($d_38 as $value) {
    echo "
        <option value='".$value."'";
            if ($results["q".$i]==$value) echo 'selected="selected"';     
    echo">".$value."</option>
";
}

I currently have the the information stored in an array called $d_38 this information is placed into the options of the drop down during the foreach loop.

That all works fine. However, I have a different language stored in $d_38_t that I want to show when the text of the option is shown, in the code above this is the third $value variable. So basically, the user sees the options in one language but the data is always stored in English in this case.

I've no idea how to put those two arrays together so I can use them in the foreach loop - can anyone offer any guidance please?

I feel like this is missing php, no? -- And, FWIW, this isn't a jQuery question at all. EDIT Much better. — Brad Christie
– Brad Christie, Commented Jun 5, 2015 at 19:43
I'm suitably embarrassed...been entrenched with jQuery today...hence it's on my brain...thanks Brad! — Homer_J
– Homer_J, Commented Jun 5, 2015 at 19:44
Probably much easier to use a regular for loop to iterate over one array and inside access data from both arrays, provided they are sorted the same way. — HaukurHaf
– HaukurHaf, Commented Jun 5, 2015 at 19:45

pavel · Accepted Answer · 2015-06-05 19:47:58Z

3

Add key to foreach and use it in as the key of $d_38_t.

foreach ($d_38 as $key => $value) {
    echo "<option value='" . $value . "'";
        if ($results["q".$i] == $value) echo 'selected="selected"';    
    echo ">" . $d_38_t[$key] . "</option>";
}

answered Jun 5, 2015 at 19:47

pavel

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1 Comment

Brad Christie Over a year ago

Probably better to stick with foreach. Keys may not be numeric, and foreach will retain this relationship.

Brad Christie · Accepted Answer · 2015-06-05 19:47:49Z

3

Assuming the keys are numeric and align between $d_38 and $d_38_t, you can use a for loop:

for ($i = 0; $i < count($d_38); $i++)
{
    // ...snip...
    echo ">" . $d_38_t[$i] . "</option>";
}

Going to keep it, but do be warned: this only works with numeric keys. @panther has the correct answer. ;-)

answered Jun 5, 2015 at 19:47

Brad Christie

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