remove a string inside a string with regex

Question

I would like to remove a part of a string like in the example below (with a regex and preg_replace) :

abcd,{{any_word |same_word_but_to_keep}},efg...

Result should be :

abcd,{{same_word_but_to_keep}},efg...

Any idea?

Another example :

Bellevue,Bergouey |Bergouey(tokeep),Bourdious

Results should be :

Bellevue,Bergouey,Bourdious

Thanks a lot!!

Until it is clear what is the pattern of the word or what are the words to be removed how are we supposed to answer. — Rakholiya Jenish
– Rakholiya Jenish, Commented Jun 6, 2015 at 10:09
thanks for your answer, I updated the question, maybe it's more clear like that, any idea how to build that regex? — Julien
– Julien, Commented Jun 6, 2015 at 10:13
Do you want any duplicates of a word following | to be removed? Could you add more examples? — thodic
– thodic, Commented Jun 6, 2015 at 10:13
yes, to remove the word duplicated with "|" just before the word to keep — Julien
– Julien, Commented Jun 6, 2015 at 10:15

hwnd · Accepted Answer · 2015-06-06 12:26:05Z

2

You could use the following regex:

$str = 'Bellevue,Bergouey |Bergouey,Bourdious';
$str = preg_replace('~(\w+)\s*\|(\1)~', '$2', $str);
echo $str; //=> "Bellevue,Bergouey,Bourdious"

answered Jun 6, 2015 at 12:26

hwnd

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Community · Accepted Answer · 2020-06-20 09:12:55Z

1

Try:

preg_match_all("/\|(.*?) /", $your_string, $matches);
foreach ($matches[1] as $match) {
    $your_string = preg_replace("/([^\|]|^)$match/", "", $your_string);
}
$your_string = preg_replace("/\|/", "", $your_string);

How it works

preg_match_all("/\|(.*?) /", $your_string, $matches) Gets all the words following |
preg_replace("/([^\|]|^)$match/", "", $your_string) Removes all occurrences of the match not preceded by | and accounts for if the matching word is at the start of the string with |^
preg_replace("/\|/", "", $your_string) Removes all occurances of | from the string

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Jun 6, 2015 at 10:12

thodic

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1 Comment

Julien Over a year ago

thank you OhAuth, but the words are not separated only with a space (can be also with a coma), I updated the question, the structure with duplicates is always between {{..}}, maybe it can make it eaisier, it's probably sthg stupid, any idea?

Toto · Accepted Answer · 2015-06-06 12:04:40Z

1

I'd do:

preg_replace('/(\w+),(\w+)\s*\|\2,(.+)/', "$1,$2,$3", $string);

Explanation:

  (\w+) : group 1, a word
  ,     : a comma
  (\w+) : group 2, a word
  \s*   : white spaces, optional
  \|    : a pipe character
  \2    : back reference to group 2
  ,     : a comma
  (.+)  : rest of the string

answered Jun 6, 2015 at 12:04

Toto

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Comments

Julien · Accepted Answer · 2015-06-06 12:26:26Z

0

Finally I found a solution without a regex, it works perfectly :

$mystring="Arance,la Campagne,Gouze |Gouze,Lendresse";
$tmp="";
$words=explode(",",$mystring);
foreach($words as $word){
    if(strpos($word,"|")){
            $l=explode("|",$word);
            $tmp=$tmp.$l[1].",";
    }else{$tmp=$tmp.$word.",";}
}
$mystring=$tmp;

answered Jun 6, 2015 at 12:26

Julien

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