How to create char array of predefined size while input at runtime?

Question

I need to store input1 input2 input3 in char array of given same size.

public static void evalCharArray(int size){

      System.out.println("please enter any three string not exceed than size"+size); 
         Scanner sc=new Scanner(System.in);
         String input1=sc.nextLine();
         String input2=sc.nextLine();
         String input3=sc.nextLine();
        //what i need is-I want to store these input string in three separate charArray of same length(ie of int size)
  }

If i am using input1.toCharArray() input2.toCharArray() input3.toCharArray() these are giving me array of different size based on input.

input1, input2, and input3 in a single char array? or 3 separate char array with the same size? — almightyGOSU
– almightyGOSU, Commented Jun 9, 2015 at 6:56
please enter any three string not exceed than size what does that mean? — Naman Gala
– Naman Gala, Commented Jun 9, 2015 at 7:00
What if the user enters a string more than size characters? — Spikatrix
– Spikatrix, Commented Jun 9, 2015 at 7:01
@NamanGala this size is the size of char array since we have to put it into char array of length size. — user4768611
– user4768611, Commented Jun 9, 2015 at 7:02

Naman Gala · Accepted Answer · 2015-06-09 07:07:17Z

3

You can use System.arraycopy() method.

You can use this sample code.

public static void main(String[] args) {
    String s = "work";
    char[] arr = new char[10];
    System.arraycopy(s.toCharArray(), 0, arr, 0, s.toCharArray().length );
    System.out.println(arr.length); // prints 10
    System.out.println(arr); // prints work
}

answered Jun 9, 2015 at 7:07

Naman Gala

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Codebender · Accepted Answer · 2015-06-09 07:10:18Z

3

Use Arrays.copyOf(T[], int).

 char[] input1=Arrays.copyOf(sc.nextLine().toCharArray(), size);

Copies the specified array, truncating or padding with nulls (if necessary) so the copy has the specified length.

edited Jun 9, 2015 at 7:10

answered Jun 9, 2015 at 7:07

Codebender

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