Is it possible to declare a function returning an array? [duplicate]

Question

I tried this:

int ([]foo)();
int[] foo();
int (foo[])();

But it didn't declare what I expected. Is it possible?

I don't mean declaring a function returning a pointer. I need to return exactly an array.

What is the difference between a pointer and an array, for you ? — Telokis
– Telokis, Commented Jun 9, 2015 at 11:00
You can't return an array, but you can return a reference to an array, or a std::array. What do you actually need this for? — TartanLlama
– TartanLlama, Commented Jun 9, 2015 at 11:00
@Ninetainedo Well, it's the different type. It's not only for me, it's for all. The thing that there's the array-to-pointer conversion and arrays're adjusted to pointers when they're odr-used — user3663882
– user3663882, Commented Jun 9, 2015 at 12:40
I am really curious about your requirements because the array will be implicitly turned into a pointer. So what will it change, concretly ? — Telokis
– Telokis, Commented Jun 9, 2015 at 13:11

Community · Accepted Answer · 2017-05-23 12:14:24Z

0

What you want to return from your function is actually a pointer to the first element in the array:

int* arr(int arr[]);

for more information look at this function.

CommunityBot

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answered Jun 9, 2015 at 11:01

israel altar

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2 Comments

You should be more explicit because of the I don't mean declareing a function returning a pointer. part of the question.

added a link to the answer