php extract function get variable value

Question

I have a large datatable form. I like to set the database variables dynamically in this case the form input value submitted is 99

$nbs = array();
    foreach ($rows as $r) {
        $dec1 = 'q' . $r["sort"] . 'z1';
        $dec2 = '(int) $_POST["q' . $r["sort"] . 'z1"]';
        $nbs[$dec1] = $dec2;
                        }

extract($nbs);

This creates the following:

 $q1000z1 = (int) $_POST[q1000z1];
 var_dump($q1000z1);

outputs: string(27) "(int) $_POST["q100000z1"]"

but if i write the code

      $q1000z1 = (int) $_POST[q1000z1];
      var_dump($q1000z1);

outputs: 99

I like to get the 99 but something is wrong in my extract method because it doesn't get referenced to the form input value? Any suggestions?

mario · Accepted Answer · 2015-06-10 05:08:52Z

1

Don't put the $_POST[…] expression in a string. Just do:

 $dec2 = (int) $_POST[$dec1];

You already assembled the array index $dec1 there. So just use it for literal array access. Afterwards $dec2 contains the desired $_POST input value.

(Now what you generally don't want to do is use extract() there. That only makes sense to unfold small in-application arrays. For larger structures, just keep and work with the $nbs array instead.)

answered Jun 10, 2015 at 5:08

mario

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