function with parameters as an array with objects javascript

Question

I had a problem where i sa feeding an Function with an array with objects inside.

var func = function (){
    var feeded = //here is my problem
    /*some code/*
}

var itemArray = [{"stat":49,"amount":156},{"stat":40,"amount":108},{"stat":5,"amount":207},{"stat":7,"amount":311}] //just an exsample
var answare = func(itemArray)

How do i med the variable feeded the same as itemArray, so i can use the methods for arrays on feeded?

I have tried useing:

var feeded = [].slice.call(arguments)

and

var feeded = arguments

I could not use a for loop and then get the stat and amount inside. (i am not needing to close lines as it is not needed in google script

You are overthinking it. var func = function(feeded) { ... } should work for you, given that you are invoking it with func(itemArray). Alternately, var func = function() { var feeded = arguments[0]; ... }, if you really, really hate that parameter there. It would be a different matter if you invoked func.apply(this, itemArray), but there is no reason to. — Amadan
– Amadan, Commented Jun 10, 2015 at 6:57
You should read a tutorial about functions, such as developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Functions or eloquentjavascript.net/03_functions.html — Felix Kling
– Felix Kling, Commented Jun 10, 2015 at 6:59
if you say `var func = funtion(feeded), feeded is only the first object, as all that is feeded to the funtion becomes an array, you juts name the first object inside the array — Meltinglava
– Meltinglava, Commented Jun 10, 2015 at 8:57
@MeltinglavaOutland: As I said, as long as you are passing one argument, like func(itemArray), you are only getting a single argument in the function. You don't need to access arguments unless you want to handle the syntax func(), func(item), func(item, item)... and not func(itemArray). — Amadan
– Amadan, Commented Jun 11, 2015 at 4:45

Markai · Accepted Answer · 2015-06-10 06:59:00Z

1

You need to make the function accept a parameter. Simply put a suitable name for the parameter in the parentheses of your the function declaration like this:

var func = function(items){
    [...]
}

Inside the function, you can access the parameter by simply using it's name. In your case it would be like this:

var func = function(items){
    var feeded = items;
}

You can read more about functions in javascript here

answered Jun 10, 2015 at 6:59

Markai

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Comments

Iwan1993 · Accepted Answer · 2015-06-10 06:59:44Z

0

Actually you can iterate those with a for Loop

var func = function (){
    var feeded = arguments;
    console.log(arguments);
    for(var i = 0; i < feeded[0].length; i++)
        console.log(feeded[0][i].stat);
}

var itemArray = [{"stat":49,"amount":156},{"stat":40,"amount":108},{"stat":5,"amount":207},{"stat":7,"amount":311}] //just an exsample
var answare = func(itemArray)

You might just have forgot to access arguments[0] instead of arguments

answered Jun 10, 2015 at 6:59

Iwan1993

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7 Comments

ozil Over a year ago

what is arguments ??

Iwan1993 Over a year ago

arguments is an array of arguments given, but not defined in parameters of function e.g. func('a', 'b'); would have arguments[0] == 'a' and arguments[1] == 'b'

ozil Over a year ago

arguments is a key world?/

David Knipe Over a year ago

arguments isn't quite an array, but [].slice.call(arguments) will return its contents as an array.

Meltinglava Over a year ago

So it is an array inside an array. That explains why i got arguments.length = 1.

|

Walter Chapilliquen - wZVanG · Accepted Answer · 2015-06-10 07:12:24Z

0

Try:

var func = function (){
    var feeded = arguments; //is itemArray Array
    console.log(feeded)
    /*some code*/
}

var itemArray = [{"stat":49,"amount":156},{"stat":40,"amount":108},{"stat":5,"amount":207},{"stat":7,"amount":311}] //just an exsample
var answare = func.apply(null, itemArray)

edited Jun 10, 2015 at 7:12

answered Jun 10, 2015 at 7:02

Walter Chapilliquen - wZVanG

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2 Comments

ozil Over a year ago

what is arguments ??

Walter Chapilliquen - wZVanG Over a year ago

arguments = itemArray[]

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