How to select randomly from a list of string-array

Question

I have a list of string arrays:

<string-array name="chapter_1">
      <item>......</item>
      .           
      .
      .
      .
</string-array>

<string-array name="chapter_2">
      <item>......</item>
      .           
      .
      .
      .
</string-array>

and so on. I have got a random int chapter_no.

I have a string:

String chapter_name = "chapter_" + chapter_no;

Now, I want to access string array corresponding to the chapter_no.

I know that I can't do like this:

String[] chapter = getResources().getStringArray(R.array.chapter_name);

How can I access the string arrays randomly? Please help me.

Do you want a random String Array or a random String from a known chapter? — Japheth Ongeri - inkalimeva
– Japheth Ongeri - inkalimeva, Commented Jun 10, 2015 at 12:27
First I want to get string array and then a string from chapter. Let me say I want a random string ( item ) from chapter. — learner
– learner, Commented Jun 10, 2015 at 12:29
Do u want random string(item) from any specific chapter or from all? — Apurva Kolapkar
– Apurva Kolapkar, Commented Jun 10, 2015 at 12:31
@learner can 't u iterate through the element and find the element you are looking for? — nafas
– nafas, Commented Jun 10, 2015 at 12:32
If I understand you correctly, then @Moinkhan 's answer should help you achieve what you want — Japheth Ongeri - inkalimeva
– Japheth Ongeri - inkalimeva, Commented Jun 10, 2015 at 12:38

Moinkhan · Accepted Answer · 2015-06-10 13:18:48Z

2

To get Random String from chapter_array ..

String[] chapter = getResources().getStringArray(R.array.chapter_name);

String randomString = chapter[new Random(chapter.length).nextInt()];

[Updated]

        String[] data;

        //first of all give all resources to arrays
        int[] arrays = {R.string.chapter_1, R.string.chapter_2};

        //then we are fetching any one string array resources randomly
        int chapter_no = arrays[new Random(arrays.length).nextInt()];

        //From above we got any one random resource string..So we fetch all string items from that resource into data array
        data = getResources().getStringArray(chapter_no);

        //Now from that data array we fetch any one random string.
        String randomString = data[new Random(data.length).nextInt()];

[updated]

    String[] data;
    int[] arrays = {R.array.chapter_1, R.array.chapter_2};
    int chapter_no = arrays[new Random().nextInt(arrays.length-1)];
    data = getResources().getStringArray(chapter_no);
    String randomString = data[new Random().nextInt(data.length-1)];
    Toast.makeText(this, randomString, Toast.LENGTH_SHORT).show();

edited Jun 10, 2015 at 13:18

answered Jun 10, 2015 at 12:32

Moinkhan

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9 Comments

Moinkhan Over a year ago

I want to make sure one thing ,... the chapter_name is available to you or not ....???

learner Over a year ago

chapter_name is a variable, not a constant.. Please go through question. It is not working at all and I tried it..

learner Over a year ago

Yeah, I got a solution like this here: stackoverflow.com/questions/12139015/… But I don't want to make an array because there are 100 chapters.

Moinkhan Over a year ago

But if you are talking about 100 chapters then you should have to Sqlite ... which is batter option for you..

learner Over a year ago

I know that. but I am using string-array. And also using array instead of string works..

|

Nagaraju V · Accepted Answer · 2015-06-10 13:01:43Z

1

Once try as follows

UPDATE

int id = getResources().getIdentifier(chapter_name, "array",this.getPackageName()); 
String[] chapter = getResources().getStringArray(id);

Hope this will helps you.

edited Jun 10, 2015 at 13:01

answered Jun 10, 2015 at 12:33

Nagaraju V

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2 Comments

learner Over a year ago

Your answer is working well. thank you for the answer. I can't find any documentation for the topic. Please suggest me one.

Nagaraju V Over a year ago

@learner i am also new to this i referred following developer.android.com/reference/android/content/res/…

Francisco Romero · Accepted Answer · 2015-06-10 12:30:49Z

0

If you just have 2 strings and you want to get them randomly you can do it like this:

Random random = new Random();

int chapter_no = random.nextInt(2) + 1;
String chapter_name = "chapter_" + chapter_no;

This Random function that I put above will get values until number 2.

I expect it helps to you!

answered Jun 10, 2015 at 12:30

Francisco Romero

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3 Comments

learner Over a year ago

I have more than 2 string arrays and corresponding chapter no.

Francisco Romero Over a year ago

@learner and do you know exactly the number of string arrays that you have there?

Francisco Romero Over a year ago

@learner Then you can change the number inside the nextInt witht the number of string-arrays that you have (the total). random.nextInt(total) + 1;

Kartheek · Accepted Answer · 2015-06-10 12:34:26Z

0

Create an array of all those array ids, and then pick one of them in that array.

int[] arrays = {R.array.chapter_1,....};

Randomly pick one among these array.

 Random random = new Random();
 int chapter_no = arrays[random.nextInt(arrays.length)];

edited Jun 10, 2015 at 12:34

answered Jun 10, 2015 at 12:29

Kartheek

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2 Comments

learner Over a year ago

As described in the given question? Can't i have a better solution? stackoverflow.com/questions/12139015/…

Kartheek Over a year ago

but you have an array of string-array.

Apurva Kolapkar · Accepted Answer · 2015-06-10 13:02:35Z

0

You Can Do this :

String[] chapter = getResources().getStringArray(R.array.chapter_1);
String[] chapter2 = getResources().getStringArray(R.array.chapter_2);
Random rand=new Random();
int randomNo=rand.nextInt();


ArrayList<String> temp = new ArrayList<String>();
temp.addAll(Arrays.asList(chapter));
temp.addAll(Arrays.asList(chapter2));
String [] concatedArgs = temp.toArray(new String[chapter.length+chapter2.length]);
String item=concatedArgs[randomNo];

edited Jun 10, 2015 at 13:02

answered Jun 10, 2015 at 12:37

Apurva Kolapkar

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2 Comments

learner Over a year ago

I don't want this solution man. This will select from chapter_2. I want to get from any chapter.

learner Over a year ago

please don't delete the previous answer.. some times other users get confused. and write edit on the top of the answer.. I will try your solution also.

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