How to request file with array name of input file?

Question

Just wondering why I can't get value of array name from input type file.

HTML:

<input type="file" name="collateral_photo[]" id="collateral_photo" class="default"/>

The name of this input file is an array.

PHP Laravel

return Request::file('collateral_photo');

The return result is [{}]

What I want right now just how to get value from this input file with array name.

Please, please help me out.

Thank you very much for any help.

You may have forgot to add enctype="multipart/form-data" to your form. — chanafdo
– chanafdo, Commented Jun 11, 2015 at 2:39

Sourabh Kumar Sharma · Accepted Answer · 2015-06-11 02:18:59Z

16

use the below code, since the name attribute is an array

$files = Request::file('collateral_photo');
return $files[0];

or if you want second file

return $files[1];

//if you want to access second file and so on

you need to access the file with array index specified.

If you want to return the whole files array itself then use

return $files

edited Jun 11, 2015 at 2:18

answered Jun 11, 2015 at 2:09

Sourabh Kumar Sharma

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5 Comments

Tum Lina Over a year ago

@Sourabh...If I use this, the return result get nothing. :(

Sourabh Kumar Sharma Over a year ago

what is the result of var_dump() ?

Tum Lina Over a year ago

surly if I return with specified offset like return $files[0], it show me the value. But if I try with return $files, it give me this [{}].

Sourabh Kumar Sharma Over a year ago

i do not see any reason for it return [{}], can you post the code in your question where you are accessing it? Might be you are accessing it in a wrong manner

Tum Lina Over a year ago

Ohhh...I solved it now. I used return with specified offset to loop the value. Thanks very much. :)

Yevgeniy Afanasyev · Accepted Answer · 2017-08-28 06:08:42Z

4

And going one step further we can work with multiple-level-arrays like so:

<input name="channel[1][file]" type="file">
<input name="channel[2][file]" type="file">

in laravel you would need a structure

$files = $request->file('channel');
$file1 = $files[1]['file'];
$file2 = $files[2]['file'];

answered Aug 28, 2017 at 6:08

Yevgeniy Afanasyev

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1 Comment

tranthaihoang Over a year ago

It works fine for me! in conjunction with this check function $request->hasFile("channel.1.file")

Bilaal Rashid · Accepted Answer · 2019-04-11 19:31:04Z

3

If it is an array of files do:

$request()->file($fieldName)[$key]->getClientOriginalName();

edited Apr 11, 2019 at 19:31

Bilaal Rashid

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answered Apr 11, 2019 at 17:19

Magno Max

311 bronze badge

1 Comment

Snoxik Over a year ago

remove "()" on request and working, $request->file($fieldName)[$key]->getClientOriginalName();

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