help me translate Java code making use of bytes into jython code

Question

how do I translate this code into jython?

     ZipOutputStream zos = new ZipOutputStream(new FileOutputStream(file + ".zip"));
     byte[] buf = new byte[1024];
     int len;
     //Create a new Zip entry with the file's name.
     ZipEntry zipEntry = new ZipEntry(file.toString());
     //Create a buffered input stream out of the file
     //we're trying to add into the Zip archive.
     FileInputStream fin = new FileInputStream(file);
     BufferedInputStream in = new BufferedInputStream(fin);
     zos.putNextEntry(zipEntry);
     //Read bytes from the file and write into the Zip archive.
     while ((len = in.read(buf)) >= 0) {
        zos.write(buf, 0, len);
     }
     //Close the input stream.
     in.close();
     //Close this entry in the Zip stream.
     zos.closeEntry();

this is what I have but it Fails badly

            buf=None                                     <<<< ?
            len=None                                     <<<< ?
            zipEntry=ZipEntry(file.toString()) 
            fin=FileInputStream(file)
            bin=BufferedInputStream(fin)
            self._zos.putNextEntry(zipEntry)
            while (len=bin.helpme_im_dying(buf)) >= 0):  <<<< ?
                self._zos.write(buf,0,len)               <<<< ?
                len = bin.read(buf)                      <<<< ?
            bin.close()
            self._zos.closeEntry()

refer to this page for information https://www.acm.org/crossroads/xrds6-3/ovp63.html

Why the buffered stream when you are using it a chunk at a time anyway? — Tom Hawtin - tackline
– Tom Hawtin - tackline, Commented Nov 26, 2008 at 13:08

C. K. Young · Accepted Answer · 2008-11-21 08:46:24Z

4

Here's an exact translation of that function (except, like your case, using bin instead of reserved keyword in).

from jarray import zeros
from java.io import BufferedInputStream, FileInputStream, FileOutputStream
from java.util.zip import ZipEntry, ZipOutputStream

def test(file):
    zos = ZipOutputStream(FileOutputStream(file + ".zip"))
    buf = zeros(1024, 'b')
    zipEntry = ZipEntry(file)
    fin = FileInputStream(file)
    bin = BufferedInputStream(fin)
    zos.putNextEntry(zipEntry)
    len = bin.read(buf)
    while len >= 0:
        zos.write(buf, 0, len)
        len = bin.read(buf)
    bin.close()
    zos.closeEntry()

answered Nov 21, 2008 at 8:46

C. K. Young

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2 Comments

Setori Over a year ago

nice i never knew about jarray. thank you Chris I really appreciate it

C. K. Young Over a year ago

I didn't know about jarray until you asked your question. :-P I found it here: jython.org/Project/userguide.html

jfs · Accepted Answer · 2008-11-21 11:32:26Z

1

It is not an answer to your question, but related. Here is a CPython version:

from zipfile import ZipFile, ZIP_DEFLATED

def test(file):
    ZipFile(file+".zip", "w", ZIP_DEFLATED).write(file)

edited Nov 21, 2008 at 11:32

answered Nov 21, 2008 at 11:19

jfs

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1 Comment

Setori Over a year ago

yeah isnt that just great! so smooth

Greg Allen · Accepted Answer · 2014-09-04 10:16:30Z

0

Don't use ZipFile without ensuring it is closed:

with ZipFile('spam.zip', 'w') as myzip:
    myzip.write('eggs.txt')

answered Sep 4, 2014 at 10:16

Greg Allen

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