For instance, the array is
link2_pathname
link1_pathname
link3_pathname
How can I get the array like below.
link1_pathname
link2_pathname
link3_pathname
Thanks a lot in advance!
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1stackoverflow.com/questions/7442417/…Steephen– Steephen2015-06-17 02:31:28 +00:00Commented Jun 17, 2015 at 2:31
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2 Answers
pipe a loop to sort.
a=(l2 l3 l1)
b=($(for l in ${a[@]}; do echo $l; done | sort))
you probably need to watch out for the IFS when handling string values containing spaces.
2 Comments
liam xu
thanks. I tested this script, why it output l2 when I echo $a. I want to output l2,l3,l1
Marc Bredt
i do not know bash's inner handling of the IFS when printing an array.
@ or * expand to all entries in an array. you might want to access or print the values contained by echo ${a[@]}. ${a} probably just returns l2 because the default IFS, which is a space is recocognized and therefor cut off due to uncomplete variable expansion.try this
var=( link2_pathname link1_pathname link3_pathname )
for arr in "${var[@]}"
do
echo $arr
done | sort
new_var=( $(for arr in "${var[@]}"
do
echo $arr
done | sort) )
