Read JSON double dimensional array in Java

Question

I'm trying to get a string from a JSONObject.

My JSON looks like this :

{
    "agent":
    [
        {"name":"stringName1", "value":"stringValue1"},
        {"name":"stringName2", "value":"stringValue2"}
    ]
}

I want to get the values from stringName1 and stringName2. So first, I tried to get the "agent" using this :

JSONObject agent = (JSONObject) jsonObject.get("agent");

However, this throws me an error.

Have you got any idea on how to process ?

"agent" is JSONArray. jsonObject.optJSONArray("agent");

Blackbelt
– Blackbelt

2015-06-23 14:03:32 +00:00
Commented Jun 23, 2015 at 14:03 — Blackbelt
– Blackbelt, Commented Jun 23, 2015 at 14:03

Hadi Satrio · Accepted Answer · 2015-06-23 14:06:49Z

3

You're trying to parse a JSON array into a JSON object. Of course it's going to give you errors.

Try this instead:

JSONArray agent = jsonObject.getJsonArray("agent");

// To get the actual values, you can do this:
for(int i = 0; i < agent.size(); i++) {
    JSONObject object = agent.get(i);
    String value1 = object.get("name");
    String value2 = object.get("value");
}

edited Jun 23, 2015 at 14:06

answered Jun 23, 2015 at 14:04

Hadi Satrio

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2 Comments

Mauker Over a year ago

And to get the elements in the Array, use the get(int) method. Like: agent.get(0);.

Antoine Delia Over a year ago

Thanks for your help ! I had to change some code but it works ! I changed agent.size() to agent.length() and object.get("name") to object.getString("name").

kavetiraviteja · Accepted Answer · 2015-06-23 15:23:40Z

0

 String Json=" { agent: [ {name:stringName1, value:stringValue1},{name:stringName2, value:stringValue2}]}";

You are parsing Jsonarray in to JsonObject that is why you are getting error.

JSONObject obj = new JSONObject(Json);
JSONArray array = obj.getJSONArray("agent");

 for(int i = 0 ; i < array.length() ; i++)
       {
   String strngNameOne=array.getJSONObject(i).getString("name");
   String stringNameTwo=array.getJSONObject(i).getString("value");
   //System.out.println(array.getJSONObject(i));
        }

answered Jun 23, 2015 at 15:23

kavetiraviteja

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