Bash Script - Piping commands to echo

Question

I have this command :

echo rm $(find "$SD" -type f -mtime "+$MT" -name "*.$TY" -print ) >> ${LOGFILE}

and it prints

rm /u01/oradata/logs/dwf_monitor_datafile.dbf.gz /u01/oradata/logs/dws_monitor_datafile.dbf.gz /u01/oradata/logs/dwd_monitor_datafile.dbf.gz

I want it to instead print

rm /u01/oradata/logs/dwf_monitor_datafile.dbf.gz 
rm /u01/oradata/logs/dws_monitor_datafile.dbf.gz 
rm /u01/oradata/logs/dwd_monitor_datafile.dbf.gz

How, thanks in adcance.

John1024 · Accepted Answer · 2015-06-26 18:28:47Z

3

If you actually want to delete the files, you should use find's -delete command. If you are just trying to display nice-looking output, then try:

find "$SD" -type f -mtime "+$MT" -name "*.$TY" -exec echo rm {} \; >>${LOGFILE}

answered Jun 26, 2015 at 18:28

John1024

115k15 gold badges152 silver badges183 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

user1918074 Over a year ago

I am already doing that, I just want to generate this code for a manual delete later on. Something that you cut from the log and paste onto command line and run the actuals. The data may change thats why.

John1024 Over a year ago

@user1918074 Did you try the find command in my answer for that? In what way was its output not satisfactory for your purposes?

Collectives™ on Stack Overflow

Bash Script - Piping commands to echo

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related