This is my loop:
sure = input('Are you sure that you wish to reset the program?(y/n)')
while sure != 'y' or sure != 'n':
sure = input('Please awnser y or n, Are you sure that you wish to reset the program?(y/n)')
The loop carries on looping even if y or n are entered.
Change the condition to
while sure != 'y' and sure != 'n':
Your condition as written will always be True no matter what they enter. An alternative would be
while sure not in ('y','n'):
You need to do and instead of or . When doing or it will continue to the loop if sure is not y as well n , but sure cannot be both at the same time, hence it loops forever.
Example -
sure = input('Are you sure that you wish to reset the program?(y/n)')
while sure != 'y' and sure != 'n':
sure = input('Please awnser y or n, Are you sure that you wish to reset the program?(y/n)')
The problem is in your logical expression:
sure != 'y' or sure != 'n'
Using De Morgan's Law, this could be rephrased as:
!(sure == 'y' and sure == 'n')
Obviously, sure can never be both 'y' and 'n', so this doesn't work. What you want instead is:
sure != 'y' and sure != 'n'
