Angularjs ng-init with ng-selected issue

Question

In the following code if ng-selected value does not become True then why does ng-init not select the option value=3 . If ng-selected becomes true it should show the value selected else the default value i.e, option 3

Right drop down shows no option selected.

<select class="form-control" name="issue" id="issue" ng-model="item.issue" ng-init="item.issue='3'">
     <option value="3" ng-selected="item.issue['id'] == '3'">Task</option>
     <option value="4" ng-selected="item.issue['id'] == '4'">Task4</option>
</select>

Davin Tryon · Accepted Answer · 2015-07-03 08:02:10Z

2

In ng-init you are setting issue to '3', not item.issue.id.

<select class="form-control" name="issue" id="issue" ng-model="item.issue" ng-init="item.issue.id='3'">
     <option value="3" ng-selected="item.issue['id'] == '3'">Task</option>
     <option value="4" ng-selected="item.issue['id'] == '4'">Task4</option>
</select>

answered Jul 3, 2015 at 8:02

Davin Tryon

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2 Comments

Rajeev Over a year ago

some how its still not showing up the value even if i set it to ng-init="item.issue.id='3'"

Davin Tryon Over a year ago

What are you setting item.issue to in your controller? You may need, item.issue = { id: '3' }. OR something like item = { issue: { id: '3' }}

Shubham Nigam · Accepted Answer · 2015-07-03 08:02:07Z

0

I think ng-init should set value of id

<select class="form-control" name="issue" id="issue" ng-model="item.issue" ng-init="item.issue.id='3'">
     <option value="3" ng-selected="item.issue['id'] == '3'">Task</option>
     <option value="4" ng-selected="item.issue['id'] == '4'">Task4</option>
</select>

answered Jul 3, 2015 at 8:02

Shubham Nigam

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