I really can't see what the issue is with my script is. I've considered missing quotations or other syntax errors. There's got to be something I'm missing. It's a very simple while loop script...
#!/bin/bash
c=1
while [ $c -le 5 ]
do
echo "Welcone $c times"
c=$(( c++ ))
done
I should mention that I'm running bash in cygwin on windows 7.
thanks for the help
Change:
c=$(( c++ ))
to
(( c=c+1 ))
When Bash sees: (( var)) it will try and 'do some math' on contents... In this case 'c++' == empty string == '0'; c will always be equal to '1' due to 1st assignment...
From the Bash man page on my Linux system (you may need to review this for Cygwin - could be different...):
((expression)) The expression is evaluated according to the rules described below under ARITHMETIC EVALUATION. If the value of the expression is non-zero, the return status is 0; otherwise the return status is 1. This is exactly equivalent to let "expression".
Also:
id++ id--
variable post-increment and post-decrement
++id --id
variable pre-increment and pre-decrement
After a little testing, the 'pre-increment' seems to do what you are after here - note that you may need to declare 'c' as an integer:
typeset -i c=1
while [ $c -le 5 ]
do
echo "Welcone $c times"
c=++c
# (( c=c+1 ))
done
dos2unixto convert it (and read the man page, it overwrites its input).tr -d '\r' < your-script.sh > temp.sh; mv temp.sh your-script.sh