table parameter variable (basic)

Question

I have variable: $default['text']="This is default text"; and $other_text['text']="This is other text";

I would like to choose one of them in function:

function insertText($param){
  if(isset($other_text[$param]))
    echo($other_text[$param]); (*)
  else 
    echo($default[$param]); (**)
}

if instead of lines (*) and (**) I write something like: echo("other_text"); and echo("default_text"); I always receive second option. That's why I assume there is something wrong with $var[$param] construction. How should that look like?

Mindastic · Accepted Answer · 2015-07-04 21:37:45Z

1

If $default['text']="This is default text"; and $other_text['text']="This is other text"; are defined outside the function body, then you should declare them as global inside your function:

function insertText($param){
  global $default, $other_text;
  if(isset($other_text[$param]))
    echo($other_text[$param]); (*)
  else 
    echo($default[$param]); (**)
}

If you don't do that, then the check isset($other_text[$param]) will always return false.

answered Jul 4, 2015 at 21:37

Mindastic

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