Java fileinputstream No such file or directory

Question

I'm trying to learn how to use read line by line from a text file. Even though I put the txt file in the same src, the console always shows the error as - No such file or directory.

public class ddd {

public static void main(String[] args) {
    FileInputStream fis = null;
    BufferedReader reader = null;
    try {
        fis = new FileInputStream("/dd/src/com/dd/input.txt");
        reader = new BufferedReader(new InputStreamReader(fis));
        System.out
                .println("Reading File line by line using BufferedReader");
        String line = reader.readLine();
        while (line != null) {
            System.out.println(line);
            line = reader.readLine();
        }
    } catch (Exception e) {
        System.out.println(e.getMessage());
    } finally {
        try {
            reader.close();
            fis.close();
        } catch (IOException e) {
            System.out.println(e.getMessage());
        }

    }
}

} enter image description here

I might recommend using the current working directory System.getProperty("user.dir")) to find out where you are currently working. That proved to be one of the biggest issues I had when learning to use file input/output. — Sh4d0wsPlyr
– Sh4d0wsPlyr, Commented Jul 7, 2015 at 16:34

Sam Estep · Accepted Answer · 2015-07-07 16:26:41Z

6

The problem is probably here:

"/dd/src/com/dd/input.txt"

On Linux at least, this would be an absolute path. What you probably want instead is a path relative to the project root:

"src/com/dd/input.txt"

Or, if you're packaging this file into your program, use a resource stream instead of a raw FileInputStream:

InputStream is = ddd.class.getResourceAsStream("input.txt");

answered Jul 7, 2015 at 16:26

Sam Estep

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Comments

TheCodingFrog · Accepted Answer · 2015-07-07 16:32:09Z

1

You need to use relative path e.g. "src/com/dd/input.txt". I tried and it's working fine.

Output

Reading File line by line using BufferedReader
hhhh

My input.txt has hhhh content.

answered Jul 7, 2015 at 16:32

TheCodingFrog

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