Cannot get a property of a Json-String

Question

I get a Json-String from a table-API:

JS

var data = JSON.stringify($table.bootstrapTable('getSelections'));
console.log(data);

Output:

[{"name":"Chemical Entity Recogniser (ChER)","state":true}]

Now I want to get the value of "name". How do I do this?

You need to deserialize the data if you want to get any information out of it — WWZee
– WWZee, Commented Jul 8, 2015 at 16:25
Why use .stringify() if you want to get values from the data? — user1106925
– user1106925, Commented Jul 8, 2015 at 16:28
I use it from the example here: issues.wenzhixin.net.cn/bootstrap-table/#methods/… — mm1975
– mm1975, Commented Jul 8, 2015 at 16:44
@torazaburo data[0].name will give undefined values. The output is a JSON string and need to be parsed! Please stop down-voting without a valid answer! — Mr.Green
– Mr.Green, Commented Jul 8, 2015 at 18:12
@torazaburo I refer to the result of JSON.stringify as the "output". The interest of the post is that he got his "Json-String" and he needs the value of "name" out of it. I just showed him the way to do it!. Can you please review your downvote? — Mr.Green
– Mr.Green, Commented Jul 8, 2015 at 18:24

Mr.Green · Accepted Answer · 2015-07-08 18:34:44Z

2

You could directly use $table.bootstrapTable('getSelections')[0].name to get the name value

or if you still want to use stringify, convert it into a JSON-string and fetch the name value from that you could do like this:

var data = JSON.stringify($table.bootstrapTable('getSelections'));
var obj = JSON.parse(data);
console.log(obj[0].name);

Output: Chemical Entity Recogniser (ChER)

Hope this helps!

edited Jul 8, 2015 at 18:34

answered Jul 8, 2015 at 16:45

Mr.Green

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4 Comments

user663031 Over a year ago

Why are you stringifying and then immediately parsing?

Mr.Green Over a year ago

JSON.stringify turns an object in to a JSON text and stores that JSON text in a string. JSON.parse turns a string of JSON text into an object.

user663031 Over a year ago

Right, so the effect of JSON.stringify followed by JSON.parse is a no-op. Why are you suggesting doing a no-op? Your obj is precisely equivalent to what you started off with, namely $table.bootstrapTable('getSelection').

Mr.Green Over a year ago

@torazaburo I agree!. I have edited my post. Is it fine now?

user663031 · Accepted Answer · 2015-07-08 18:32:56Z

1

The result of

$table.bootstrapTable('getSelections')

is just a plain old JavaScript object. It's not JSON. There is no need to stringify it. Stringification is for turning an object into a string in order to store it or send it somewhere. That's not what you want to do. Just access the value you want directly from the JavaScript object:

var data = $table.bootstrapTable('getSelections');
data[0].name

If you unnecessarily stringify this response as you are doing, then you're just going to have to turn around and parse it again, as your "accepted" answer incorrectly suggests, which will do nothing more than give you back the object you started with in the first place.

answered Jul 8, 2015 at 18:32

user663031

Comments

Villanuevand · Accepted Answer · 2015-07-08 16:27:20Z

0

Try using:

var o = JSON.parse(data)

JSON.parse() convert an JSON object to Javascript object...

answered Jul 8, 2015 at 16:27

Villanuevand

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2 Comments

mm1975 Over a year ago

o gives me the output 'o[object Object]'

Félix Adriyel Gagnon-Grenier Over a year ago

so how to get the value of the name attribute?

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