PHP array print value with specific condition

Question

i have an array $t1 like below :

Array ( 
    [0] => Array ( 
        [cust_type] => Corporate 
        [trx] => 1 
        [amount] => 10 ) 
    [1] => Array ( 
        [cust_type] => Non Corporate 
        [trx] => 2 
        [amount] => 20 ) 
    [2] => Array ( 
        [cust_type] => Corporate 
        [trx] => 3 
        [amount] => 30 ) 
    [3] => Array ( 
        [cust_type] => Non Corporate 
        [trx] => 4 
        [amount] => 40 ))

I want to print TRX whose cust_type = Corporate. I use conditional statement inside foreach as below :

foreach ($t1 as $key => $value) {
        if($value['cust_type'] = 'Corporate')
            {
                print_r($value['trx']);
            }
        echo "<br/>";
    }

But it prints all TRX values instead of corporate only. Kindly help me, thank you.

Kanishka Panamaldeniya · Accepted Answer · 2015-07-10 03:29:30Z

1

use

if($value['cust_type'] == 'Corporate')

instead of

if($value['cust_type'] = 'Corporate')

So the final result will be

   foreach ($t1 as $key => $value) {
            if($value['cust_type'] == 'Corporate')
                {
                    print_r($value['trx']);
                }
            echo "<br/>";
        }

answered Jul 10, 2015 at 3:29

Kanishka Panamaldeniya

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Comments

Vikas Umrao · Accepted Answer · 2015-07-10 03:30:32Z

1

Use double == in place of single = in if($value['cust_type'] == 'Corporate')

answered Jul 10, 2015 at 3:30

Vikas Umrao

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